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anonymous
 5 years ago
What is the quadratic formula? What is it used for? Give an uncommon example.
anonymous
 5 years ago
What is the quadratic formula? What is it used for? Give an uncommon example.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's one of three my friend! lol.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0an uncommon example eh..... the quadratic formula is derived from a method know as "completing the square"; and is used to find the real roots of a quadratic expression (quadratic just being a fancy name for "squared").

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0there are 2 named parts to the quadratic formula that I tend to get backwards; the determinate and the discriminate..they were haveing a sale on "d" words back then and so were stuck with them

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the discriminte, if it so be called, is the part b/2a and it gives you the axis of symmetry of the parabola.... to find the vertex, the hoghest or lowest point of the parabola; we use the vertex in the equation to come up with the "y" part...make sense so far?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the other "d" word, the determinate perhaps, is a square root portion of the quad formula and it tells us whether there is: no roots, 1 root, or 2 roots.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ummmm........clear as mud. But it's mainly me.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So that would be the uncommon example?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dunno about any "uncommon" examples really, still trying to figure out what that means... maybe its talking about a quadratic that aint easily factored.....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if the square root portion has under its radical umbrella a negative #, there are no real roots; if it equals zero, then there is only 1 root, and if it is greater than zero, there are going to be 2 roots.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the quad formula is: b sqrt(b^2  4ac)  +  2a 2a here you can see the two parts :) i shoulda prolly put that up first...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No just an everyday example that might not be the first one you think of. Like, doesn't airplanes have something to do with the quadratic formula?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0SO that problem has two roots?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that is not a problem ; that is the formula to determine the roots :) the standard quadratic equation is of the form: ax^2 +bx +c where a.b.and c are numbers...coefficients..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0depending on the values of a,b,and c we can use the quadratic formula to determine its axis of symmetry, vertex coordinates, and all known solutions to y=0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets try to make up an equation and test the quad formula out.... and try to stay away from airplanes :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what are your favorite three numbers in the whole wide world... :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh wait.......it said provide a USEFUL example..... duh. Not uncommon, or whatever I wrote.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ok..7 3 and 35; lets put them into the hat....stir it up...and pick one...............3 ok, a = 3; try again................7; b = 7 .......and stir again for effect........we get a 35; c = 35

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.03x^2 +7x 35...thats a quadratic formula...is it useful? dunno. but lets try out our formula.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the first thing we should do is see if its worth trying to find any roots: sqrt((7)^2  (4)(3)(35)) if this is zero or above, were good to go. sqrt(49 + 420) = sqrt(469) its a keeper so that last part is gonna be: + sqrt(469)/2(3) the axis of symmetry is gonna be: b/2a = 7/2(3) = 7/6

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so we have a center for our parabola, its at x = 7/6 if we add and subtract the other part from this, we will know our solutions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Dear God my brain hurts.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Any useful examples to share?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(7/6) + sqrt(469)/6 = about 2.4427

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0this might be useful :) one example is the arch formed by throwing a baseball to your son.... you can determine its position with a quadratic equation.... but the "roots" of it are not that exciting :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0An arch of throwing a baseball?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the other root we got is about: 4.7761 you never seen a person throw a baseball around? it tends to go up, then comes back down into the golve of the oter person. makes for a nice arch while it flys thru the air

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah! Gotcha! Now......what do you know about Pythogorean Therorem's......or whatever it is?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i know that guy was a nutjob..... but his theorum is pretty helpful :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So was Pavlov. Ok......one sec...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There are many applications for the Pythagorean Theorem.. can you give a specific example and show with calculations how the Pythagoras theorem applies?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0this is the pyth thrm....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the square of the sum of the legs of a right trianlge are equal to the square of the hypotenuse side.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OH.....and one more on quadratics too..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nice attachment, am I supposed to color it? JK!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol..... use it as a place mat ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So that a^2 thing is the formula for that>?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it is.... the names of the variables are unimportant, but that is a common rendition of it. another one is: x^2 + y^2 = r^2 and another one is: sin^2 + cos^2 = 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all for the sum of the legs of a right triangle?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it can even be expanded to: c^2 = a^2 + b^2 2ab cos(C)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yep, since right triangle are about the easiest to use; its nice to have stuff you can use with them :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0since the cos(90) = 0, that last part vanishes in the right trianlge and your left with the sum of the squares of the sides :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok......one more the quadratics thing.....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ok....... I hope your writeing this stuff down :) I might forget it all by tomorrow :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Explain the foursteps for solving quadratic equations. Can any of these steps be eliminated? Can the order of these steps be changed? Would you add any steps to make it easier, or to make it easier to understand?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No kidding.......writing away!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ive seen this one before in here and it seems to be an odd question in general. the four steps? they might be talking about the 4 common ways that quads are facttored, but then it says to elinate one of them as tho they were all used together.....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the steps I use are: 1) look at the problem 2) factor as needed 3) write down the answer 4) go to next problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0factor left side? does that make sense?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0doesnt clarify my quandry.....no.....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0id have to look up and google it to see what its talking about to give a good answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Maybe something like this: Step 1: Find two numbers that add together to get the middle term, and multiply to get the last term. Step 2: Rewrite the equation with those numbers: Step 3: Factor the first two and last two terms separately: Step 4: If you've done this correctly, your two new terms should have a clearly visible common factor.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04) Go to the next problem? HA!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0:) yeah. there are many techniques used to factor, I have my favorites, but really, the steps you are looking for will be defined by the source you are using

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can any be elimianted?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im gonna go with a no on that one....eliminating steps just sounds bad...and Ive built alot of stairs in my day :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Could the steps be rearranged?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0gonna have to go with a no again for that one, the steps tend to be in order of what you do to get to the next one.....still sounds like a bad idea to be rearranging them.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Lol, ok....well you have been an AWESOME help up until this question anyway! Thanks so much. My brain is cramping up at this point. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Lol, I may just write down "it sounds like a bad idea to me" just to see what kind of feedback i get!.
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