A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
How do you find the infinite series of 2/(n^21)? Apparently, it's telescoping and the answer is 3/2 but I don't know how to get there.
anonymous
 5 years ago
How do you find the infinite series of 2/(n^21)? Apparently, it's telescoping and the answer is 3/2 but I don't know how to get there.

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you try using the ratio test?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait sorry, haha wrong thing! i'm just learning this section too so i'll try and work it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i actually think its geometric

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Really? It's in a section that says it's telescoping.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The directions say "Determine whether the series is convergent or divergent by expressing s(subn) as a telescoping sum. If it is convergent, find its sum."

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm well if you write out the first few terms do they cancell out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No. They just keep getting smaller and besides, they're all positive.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=2}^{\infty}=2/(n^21)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can't see any way you could manipulate that to a telescoping series, but it does seem to converege to zero
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.