anonymous
  • anonymous
How do you find the infinite series of 2/(n^2-1)? Apparently, it's telescoping and the answer is 3/2 but I don't know how to get there.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
did you try using the ratio test?
anonymous
  • anonymous
wait sorry, haha wrong thing! i'm just learning this section too so i'll try and work it out
anonymous
  • anonymous
i actually think its geometric

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anonymous
  • anonymous
Really? It's in a section that says it's telescoping.
anonymous
  • anonymous
The directions say "Determine whether the series is convergent or divergent by expressing s(subn) as a telescoping sum. If it is convergent, find its sum."
anonymous
  • anonymous
hmm well if you write out the first few terms do they cancell out?
anonymous
  • anonymous
No. They just keep getting smaller and besides, they're all positive.
anonymous
  • anonymous
\[\sum_{n=2}^{\infty}=2/(n^2-1)\]
anonymous
  • anonymous
I can't see any way you could manipulate that to a telescoping series, but it does seem to converege to zero

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