anonymous
  • anonymous
Ok can someone please help me do this in order, I get really confused: (7x^3-5x-3)/(x-2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
u sure ur equation right?
anonymous
  • anonymous
is it asking tto solve or just simplify?
anonymous
  • anonymous
solve it in a way that I can understand it (by steps)

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anonymous
  • anonymous
(7x^3-5x-3)/(x-2)=0?
anonymous
  • anonymous
?
anonymous
  • anonymous
you said solve the equation, so it must be (7x^3-5x-3)/(x-2)=0 right??? if there's only (7x^3-5x-3)/(x-2) then that is simplifying
anonymous
  • anonymous
I know I have to do: _7x^2_______________ x-2l 7x^3-5x-3 7x^3 like dividing but I get lost after
anonymous
  • anonymous
hmmmm I don't quite get what you've just written there. But can u check the question again pls? Because if that question's right, there'll be imaginary roots lol, which I don't think you've gone through,
anonymous
  • anonymous
lol ok Its just Algebra I ...and I'm supposed to divide
anonymous
  • anonymous
lol so u want the answer of the steps? :D
anonymous
  • anonymous
YES
anonymous
  • anonymous
here's answer: 7x^2+14x+23+43/(x-2)
anonymous
  • anonymous
you know how to get it right?
anonymous
  • anonymous
not really :_( like I know the 7x^2 but I get lost after that
anonymous
  • anonymous
You know this is quite hard to explain here, better in person though. So I'd suggest u to go see ur teacher about this again. Anyway, I do it in quite a weird way so... it's better to find someone else :) or maybe some other guys here can help u, ask them. sorry abt that but really nothing I can do
anonymous
  • anonymous
ask that guy amistre. Quite sure he can explain to u :)
anonymous
  • anonymous
Oh its ok yeah. Thank you though :)
anonymous
  • anonymous
oh God, I don't feel right lol. Wait me 5 mins, I'll tell you how.
anonymous
  • anonymous
lol its fine hahaha
anonymous
  • anonymous
I actually have to go... I'll ask my teacher tomorrow. Really thanks :)
anonymous
  • anonymous
ok then. I'm just gonna go 2 bed

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