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anonymous

  • 5 years ago

How do you factor -x^3+6x^2-11x+6 ??

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  1. anonymous
    • 5 years ago
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    ok

  2. anonymous
    • 5 years ago
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    what is the problem that u r facing elaborate it

  3. anonymous
    • 5 years ago
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    i just need to solve it for 0.

  4. anonymous
    • 5 years ago
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    means that u want the RHS TO BE 0 or x be 0

  5. anonymous
    • 5 years ago
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    -x^3+6x^2-11x+6=0 and then solve for x

  6. anonymous
    • 5 years ago
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    ok

  7. anonymous
    • 5 years ago
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    IV JUST WAIT FOR 2minutes

  8. anonymous
    • 5 years ago
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    ok

  9. anonymous
    • 5 years ago
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    Putting x=1 we will get:

  10. anonymous
    • 5 years ago
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    -1 + 6 -11 + 6 = 0

  11. anonymous
    • 5 years ago
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    -12 + 12 = 0

  12. anonymous
    • 5 years ago
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    so it shows that x-1 is a factor of THE EQUATION

  13. anonymous
    • 5 years ago
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    I know the answers are 1 2 and 3. But how do factor this out is my question.

  14. anonymous
    • 5 years ago
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    (-x^3 + 6x^2 -11x + 6) * -1 = 0*-1

  15. anonymous
    • 5 years ago
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    ok now

  16. anonymous
    • 5 years ago
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    x^3 - 6x^2 + 11x - 6 = 0

  17. anonymous
    • 5 years ago
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    x^3 = x^2(x-1) +x^2

  18. anonymous
    • 5 years ago
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    -6x^2 = -6x(x-1) - 6x

  19. anonymous
    • 5 years ago
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    11x = 11 ( x-1) + 11

  20. anonymous
    • 5 years ago
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    putting these values in this equation x^2(x-1) - 5x(x-1) + 6(x-1) = 0

  21. anonymous
    • 5 years ago
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    (x^2-5x+)(x-1) = 0

  22. anonymous
    • 5 years ago
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    (x(x-2) - 3(x-2) ) (x-1) = 0

  23. anonymous
    • 5 years ago
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    x-3, x-2, x-1 = 0

  24. anonymous
    • 5 years ago
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    x-3 = 0 x=3 x-2 = 0 x=2 x-1 = 0 x=1

  25. anonymous
    • 5 years ago
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    SO BYE AND REPLY ME FAST did u got it

  26. anonymous
    • 5 years ago
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    yeah thanks

  27. anonymous
    • 5 years ago
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    BYE

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