How do you factor -x^3+6x^2-11x+6 ??

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How do you factor -x^3+6x^2-11x+6 ??

Mathematics
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ok
what is the problem that u r facing elaborate it
i just need to solve it for 0.

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Other answers:

means that u want the RHS TO BE 0 or x be 0
-x^3+6x^2-11x+6=0 and then solve for x
ok
IV JUST WAIT FOR 2minutes
ok
Putting x=1 we will get:
-1 + 6 -11 + 6 = 0
-12 + 12 = 0
so it shows that x-1 is a factor of THE EQUATION
I know the answers are 1 2 and 3. But how do factor this out is my question.
(-x^3 + 6x^2 -11x + 6) * -1 = 0*-1
ok now
x^3 - 6x^2 + 11x - 6 = 0
x^3 = x^2(x-1) +x^2
-6x^2 = -6x(x-1) - 6x
11x = 11 ( x-1) + 11
putting these values in this equation x^2(x-1) - 5x(x-1) + 6(x-1) = 0
(x^2-5x+)(x-1) = 0
(x(x-2) - 3(x-2) ) (x-1) = 0
x-3, x-2, x-1 = 0
x-3 = 0 x=3 x-2 = 0 x=2 x-1 = 0 x=1
SO BYE AND REPLY ME FAST did u got it
yeah thanks
BYE

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