can anyone please help.............There are six boys and six girls at a party. In how many ways can they be seated in a row if they must sit alternating boys and girls?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
This is what I would believe to be the solution:
Assume the first seat is occupied by a boy... there are 6 possible boys that can sit in that seat. The next seat is occupied by one of six possible girls. The third seat then can be occupied by one of 5 boys (one is sitting in seat #1). And so on. This would give you 6x6x5x5x4x4x3x3x2x2. However, you should double this since we assumed a boy sat in the first seat-- there is also the possibility that a girl sits in the first seat. Therefore, the answer is:
the first person to sit down could be any gender, therefore any of the 12 people so the first entry should be 12 in my opinion. followed by the pattern i showed above.