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anonymous

  • 5 years ago

can anyone please help.............There are six boys and six girls at a party. In how many ways can they be seated in a row if they must sit alternating boys and girls?

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  1. anonymous
    • 5 years ago
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    12*6*5*5*4*4*3*3*2*2*1*1

  2. anonymous
    • 5 years ago
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    This is what I would believe to be the solution: Assume the first seat is occupied by a boy... there are 6 possible boys that can sit in that seat. The next seat is occupied by one of six possible girls. The third seat then can be occupied by one of 5 boys (one is sitting in seat #1). And so on. This would give you 6x6x5x5x4x4x3x3x2x2. However, you should double this since we assumed a boy sat in the first seat-- there is also the possibility that a girl sits in the first seat. Therefore, the answer is: 2x6x6x5x5x4x4x3x3x2x2

  3. anonymous
    • 5 years ago
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    the first person to sit down could be any gender, therefore any of the 12 people so the first entry should be 12 in my opinion. followed by the pattern i showed above.

  4. anonymous
    • 5 years ago
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    That's accounted for by the 2x

  5. anonymous
    • 5 years ago
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    i concur

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