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anonymous

  • 5 years ago

how would you go about separating this ... P' = sin(P)+cos(P^2)

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  1. anonymous
    • 5 years ago
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    Is this a differential equation?

  2. anonymous
    • 5 years ago
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    What are you trying to separate? Are you trying to integrate or find the derivative?

  3. anonymous
    • 5 years ago
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    yes sir it is de

  4. anonymous
    • 5 years ago
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    First you have to identify what kind of DE it is... First order. Non-linear. And consider some ways in which you can deal with those

  5. anonymous
    • 5 years ago
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    i am supposed to find whether it is separable, homogeneous, linear , burnoulli but not linear , exact but not separable ( circle all that apply)

  6. anonymous
    • 5 years ago
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    i have the answer key but i have no clue how to work this problem in particular like for instance most of the DE i have worked with have y and x this only has P soo what would u separate...?

  7. anonymous
    • 5 years ago
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    also i only really know how to check if something is separable and i somewhat know how to do exact but the others im unsure

  8. anonymous
    • 5 years ago
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    P' can be written as dP/dx

  9. anonymous
    • 5 years ago
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    yes i got that much down... am i over thinking it... would it just be dx =dP/( sin(P)+cos(P^2) )

  10. anonymous
    • 5 years ago
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    Separable means you need to be able to get all of the y's on one side and the x's on the other

  11. anonymous
    • 5 years ago
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    kk so i was overthinking it

  12. anonymous
    • 5 years ago
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    but do you know about homogeneous and linear and burnoulli's? like how i check to see if an ODE falls under those categories?

  13. anonymous
    • 5 years ago
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    Homogenous and linear and burnoulli's all have to do with various methods to solve a DE. You have to really understand how to go about solving those types before you can classify them

  14. anonymous
    • 5 years ago
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    ok well if i give you an example could you work it out for me and ill probably be able to figure it out from that?

  15. anonymous
    • 5 years ago
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    xyy'=(x^2)+(y^2)

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