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anonymous
 5 years ago
how do you find the area enclosed by a line, a parabola, and the xaxis?
anonymous
 5 years ago
how do you find the area enclosed by a line, a parabola, and the xaxis?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know but integrate what

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0we need to know what parabola and what line

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you have x^2 from 0 to 1 its int (0 to 1) of x^2 dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find the area enclosed by \[y=\sqrt{2x}, y=62x, and the xaxis\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0first find where they intersect

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but they intersect at three different places

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0those equation only intersect in one place :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rearrange for x in the equations, your parabola will then be the lower limit, the straight line will be the upper limit and your y limits will be from 0 to the y component of the intersection point, then it is a trivial double integral

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i will scan and show you my drawing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{y component of intersection}\int\limits_{(y^2)/2}^{1/2y+3}..and so on\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i always have to draw picture first

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0me too by visual inspection you can simplify the problem a lot

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0dana, have you looked at the pic?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i also put what i integrated

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0oops that second integral should e from 2 to 3 i messed up my line a bit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{2}\int\limits_{.5y^2}^{0.5y3}dxdy\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeaa that makes sence now, thank you!

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0there was not suppose to be an e in that sentence lol

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0because the x intercept of that y=62x is 3 not 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea his way if fine too, the double integral is just another way you can check your answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wasn't paying attention to the name there sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but on the other hand that double integral is pretty epic? can someone be my fan i think i deserve it for going all out on this question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks! i'm your fan too.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0helped people a few times but it seems a lot of people just make an account to ask a question and then leave without saying thank you

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0your welcome dana lol

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0he didnt become our fan :(

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0dana, if you come back you could have done int(3y/2y^2/2,y=0..2) and got the same thing you could have look at the functions as if yaxis was xaxis

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh thats true, to switch the problem around. and i did say thank you, for the record. you all were a lot of help! :)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0lol im sorry i didn't notice im an idiot

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are aunder a curve, use integration & subtract lower curve from upper
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