- anonymous

Randy is driving 4 miles per hour faster than Sandy and if they are 287 miles apart
after 3.5 hours then how fast is Sandy driving?

- chestercat

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- amistre64

287/4 should get you randys starting point

- amistre64

287/3.5

- anonymous

i set it up as
287=3.5S + 3.5R
R=S+4
(R being randys speed, S being sandys speed)

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## More answers

- amistre64

speed randy (time) + speed sandy (time) = 287

- amistre64

good good

- anonymous

and i got 39 for S
but thats not one of my options

- anonymous

idk what i did wrong

- amistre64

287 = (s+4)(3.5) + 3.5s
287 = 3.5s +3.5s + 14
287-14 = 7s
273 = 7s
273/7 = s
39 = s

- amistre64

maybe its a bad model :)

- amistre64

randy would be going 43 and sandy 39 right?

- anonymous

thats what i figured

- amistre64

maybe it changes if they are starting from the same spot

- anonymous

my options are
51
56
61
66
71

- amistre64

randy - Sally = 287

- amistre64

(3.5s + 14) - (3.5s) = 287 ?

- anonymous

its 39! :(

- anonymous

actually i got 0 when i did it again

- amistre64

lol try randy-287 = sally

- amistre64

nope

- anonymous

GAHHHH my teacher sucks

- amistre64

distance = speed (time) right?

- anonymous

yes
btw the last question you helped me with..the pools..i was looking at the wrong answer options..it wasnt 61

- amistre64

ohhhh...was that the one with 7.1 radius

- anonymous

yes
im just gonna yell at my teacher and tell him he gave me a faulty question

- amistre64

I get:
Dr = Ds + 287 but dunno if its gonna work :)

- amistre64

(s+4)(3.5) = s(3.5) + 287

- anonymous

got 0

- amistre64

if they start at different points and travel towards each other, but thats not in the question

- anonymous

right they are from the same point and driving away from each other

- amistre64

away from each other?

- anonymous

yeah

- amistre64

thenDr + Ds = 287 if thats the case
7s +14 = 287
7(s+2) = 287
i still get 39

- anonymous

:(

- anonymous

this class is ridiculous these are like impossible problems and i still have a whole other set of problems to start

- amistre64

if sally is not moving, does that change the dynamics of our problem?

- anonymous

yeah cuz then she would have no speed

- anonymous

and therefore would have no distance

- amistre64

think of it like this maybe....in one hour, randy if 4 miles farther.....

- amistre64

randy, at the end of 3.5 hours is 14 miles farther than sally

- anonymous

that wouldnt change the equation for sally's speed though..

- amistre64

they have traveled a distance of 273 miles if they were traveling the same speed right?

- anonymous

no because when we substitute R in for S+4 they arent

- anonymous

and the question says they are travleing different speeds

- amistre64

randy is 14 miles further than sally at 3.5 hours right?

- anonymous

yeah

- amistre64

so 287 - 14 = the distance traveled by Sally in 3.5 hours right?
273 in 3.5 hours?

- amistre64

speed equals distance/time

- amistre64

that gives me 78 mph..... but its closer :)

- anonymous

hahah and still not an option

- anonymous

I am giving up for tonight, thank you for all your help

- anonymous

:)

- amistre64

Gnite :)

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