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anonymous

  • 5 years ago

bsqrt(2)=sqrt(4b-2)

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  1. anonymous
    • 5 years ago
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    (b)sqrt(2)=sqrt(4b-2)

  2. anonymous
    • 5 years ago
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    Did you try squaring both sides?

  3. nowhereman
    • 5 years ago
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    That will work, but you have to restrict the definition set of b.

  4. anonymous
    • 5 years ago
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    yeah but got a bit confused by the first b

  5. anonymous
    • 5 years ago
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    \[b\sqrt{2} = \sqrt{4b-2}\] \[\implies (b\sqrt{2})^2 = (\sqrt{4b-2})^2\] \[\implies b^22 = 4b-2 \text{, for }b>\frac{1}{2}\] etc.

  6. anonymous
    • 5 years ago
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    what would the next step be then?

  7. anonymous
    • 5 years ago
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    divide by the 2 or add the two

  8. anonymous
    • 5 years ago
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    Moving everything to one side to get the equation equal to 0, then use the quadratic equation.

  9. anonymous
    • 5 years ago
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    oooh thank you! what about that first two though?

  10. anonymous
    • 5 years ago
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    b=2?

  11. anonymous
    • 5 years ago
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    If you want to divide the whole thing by 2 you certainly can.

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spraguer (Moderator)
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