bsqrt(2)=sqrt(4b-2)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

bsqrt(2)=sqrt(4b-2)

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

(b)sqrt(2)=sqrt(4b-2)
Did you try squaring both sides?
That will work, but you have to restrict the definition set of b.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

yeah but got a bit confused by the first b
\[b\sqrt{2} = \sqrt{4b-2}\] \[\implies (b\sqrt{2})^2 = (\sqrt{4b-2})^2\] \[\implies b^22 = 4b-2 \text{, for }b>\frac{1}{2}\] etc.
what would the next step be then?
divide by the 2 or add the two
Moving everything to one side to get the equation equal to 0, then use the quadratic equation.
oooh thank you! what about that first two though?
b=2?
If you want to divide the whole thing by 2 you certainly can.

Not the answer you are looking for?

Search for more explanations.

Ask your own question