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anonymous

  • 5 years ago

2log x- log7=log112

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  1. anonymous
    • 5 years ago
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    Do you remember your rules for adding and subtracting logs?

  2. anonymous
    • 5 years ago
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    2logx-log7 is the same as log((x^2)/7)

  3. anonymous
    • 5 years ago
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    i'l give you a hint to get you started. First you add log(7) to both sides. This should yield 2log(x) = log(112) + log (7). The formula for adding logs is log(x) + log(y) = log(x*y) as long as if you have same base. This is not all there is the 2 the questions, but it's a good way to start.

  4. anonymous
    • 5 years ago
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    this is the solution\[10^{\log(784)}=x^{2}\]

  5. anonymous
    • 5 years ago
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    which leaves you with\[\sqrt{784}=x=28\]

  6. anonymous
    • 5 years ago
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    (feel free to be my fan)

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spraguer (Moderator)
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