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anonymous
 5 years ago
Can anyone help with LaPlace transforms?
anonymous
 5 years ago
Can anyone help with LaPlace transforms?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y'’ + y = 1, y(0) = 1, y’(0) = 1

nikvist
 5 years ago
Best ResponseYou've already chosen the best response.0\[y''+y=1,y(0)=1,y'(0)=1\] \[L(y''+y)=L(1)\] \[s^2Y(s)sy(0)y'(0)+Y(s)=\frac{1}{s}\] \[(s^2+1)Y(s)=s+1+1/s,Y(s)=\frac{s+1+1/s}{s^2+1}\] \[Y(s)=\frac{s^2+s+1}{s(s^2+1)}=\frac{1}{s}+\frac{1}{s^2+1}\] \[L^{1}(Y(s))=1+\sin{x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hmm ok lemme see what it looks like compared to mine.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The second step if you were to write it all out would look like this right?\[s^2L(y)s f(0)f(0)L(y)=L(1)\]

nikvist
 5 years ago
Best ResponseYou've already chosen the best response.0correct is \[s^2L(y)sy(0)y'(0)+L(y)=L(1)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0replace f's with y's right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We're saying the same thing I'm using f's
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