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anonymous
 5 years ago
INTEGRAL CALCULUS
Integral of logarithmic functions
"Evaluate this integral of (x+3)dx/x+2
anonymous
 5 years ago
INTEGRAL CALCULUS Integral of logarithmic functions "Evaluate this integral of (x+3)dx/x+2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think you'll have to use long division first since both sides have the same power. The numerator's power must be < the denominator's power. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can u answer it? i want to compare my answer.. please?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright, did you do the long division part?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got this after diving x+3 / x+2 : 1 + 1/x+2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this what you've got?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my answer x+ln(x+2)+c is this correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hold on , let me finish :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here another example can u answer this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sure, I'll give it a try ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0integral of xdx/x^2+4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can expand the denominator and you'll get the following:\[x/(x^2+4) = x/(x+2)^2\] then you'll have to do the partial fractions part which is : \[x/(x+2)^2 = A/(x+2) + B/(x+2)^2\]....etc correct me if I'm wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you know how to integrate partial fractions, right? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, I have hinted the way for you for you to proceed ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes you know :) haven't you taken partial fractions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ther's a much simpler way to do it :) hold on no need for partial fractions here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ur answer? i want to compare my answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{} x/(x^2+4) dx\] let : \[u = x^2 +4\] \[du = 2x dx\] so : \[= 1/2 \int\limits_{} 1/u du\] \[= 1/2(\ln u) + c\] \[=[ \lnx^2+4] /2 + c\] sorry abt the complicated mess earlier ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this what you've got?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i wish you can transfer your knowledge in calculus to me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, I was so ignorant in it, but then worked hard to understand it. I took this in the beginning of the semester :), just be patient and practice more then you'll master it ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you have facebook i wish we can talk together to practice my enlish

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Unfortunately, I don't have FB, myspace or any of these stuff since I don't have time for them :( , I'm sorry.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To perfect your english, read more, listen more and communicate more :) that's it
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