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anonymous

  • 5 years ago

INTEGRAL CALCULUS -Integral of logarithmic functions "Evaluate this integral of (x+3)dx/x+2

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  1. anonymous
    • 5 years ago
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    I think you'll have to use long division first since both sides have the same power. The numerator's power must be < the denominator's power. :)

  2. anonymous
    • 5 years ago
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    can u answer it? i want to compare my answer.. please?

  3. anonymous
    • 5 years ago
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    alright, did you do the long division part?

  4. anonymous
    • 5 years ago
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    I got this after diving x+3 / x+2 : 1 + 1/x+2

  5. anonymous
    • 5 years ago
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    dividing*

  6. anonymous
    • 5 years ago
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    is this what you've got?

  7. anonymous
    • 5 years ago
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    my answer x+ln(x+2)+c is this correct?

  8. anonymous
    • 5 years ago
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    hold on , let me finish :)

  9. anonymous
    • 5 years ago
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    yes, excellent :)

  10. anonymous
    • 5 years ago
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    here another example can u answer this

  11. anonymous
    • 5 years ago
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    sure, I'll give it a try ^_^

  12. anonymous
    • 5 years ago
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    integral of xdx/x^2+4

  13. anonymous
    • 5 years ago
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    you can expand the denominator and you'll get the following:\[x/(x^2+4) = x/(x+2)^2\] then you'll have to do the partial fractions part which is : \[x/(x+2)^2 = A/(x+2) + B/(x+2)^2\]....etc correct me if I'm wrong

  14. anonymous
    • 5 years ago
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    you know how to integrate partial fractions, right? :)

  15. anonymous
    • 5 years ago
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    wers the answer?

  16. anonymous
    • 5 years ago
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    i dont know

  17. anonymous
    • 5 years ago
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    lol, I have hinted the way for you for you to proceed ^_^

  18. anonymous
    • 5 years ago
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    yes you know :) haven't you taken partial fractions?

  19. anonymous
    • 5 years ago
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    oh wait

  20. anonymous
    • 5 years ago
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    ther's a much simpler way to do it :) hold on no need for partial fractions here

  21. anonymous
    • 5 years ago
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    ur answer? i want to compare my answer

  22. anonymous
    • 5 years ago
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    \[\int\limits_{} x/(x^2+4) dx\] let : \[u = x^2 +4\] \[du = 2x dx\] so : \[= 1/2 \int\limits_{} 1/u du\] \[= 1/2(\ln |u|) + c\] \[=[ \ln|x^2+4|] /2 + c\] sorry abt the complicated mess earlier ^_^

  23. anonymous
    • 5 years ago
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    is this what you've got?

  24. anonymous
    • 5 years ago
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    1/2ln(X^2+4)+C

  25. anonymous
    • 5 years ago
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    yes, well done ^_^

  26. anonymous
    • 5 years ago
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    i wish you can transfer your knowledge in calculus to me

  27. anonymous
    • 5 years ago
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    lol, I was so ignorant in it, but then worked hard to understand it. I took this in the beginning of the semester :), just be patient and practice more then you'll master it ^_^

  28. anonymous
    • 5 years ago
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    do you have facebook i wish we can talk together to practice my enlish

  29. anonymous
    • 5 years ago
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    english

  30. anonymous
    • 5 years ago
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    Unfortunately, I don't have FB, myspace or any of these stuff since I don't have time for them :( , I'm sorry.

  31. anonymous
    • 5 years ago
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    To perfect your english, read more, listen more and communicate more :) that's it

  32. anonymous
    • 5 years ago
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    tnx

  33. anonymous
    • 5 years ago
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    np :)

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