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anonymous
 5 years ago
Need help with LaPlace transform y''y=5*sin2t when given y(0)=0, y'(0)=6
anonymous
 5 years ago
Need help with LaPlace transform y''y=5*sin2t when given y(0)=0, y'(0)=6

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I've gotten to \[2^2L(y)6y=5*\sin2t\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but I think I'm stuck... that should say s^2 not 2^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[s^2L(y)6y=5*\sin(2t)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you have the value of y'(0)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I messed that all up.... it should be\[s^2L(y)6L(y)=10/s^2+4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so what do I do from there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try to solve for L(y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I thikn I would go \[s^2(L(y)1)6=10/s^2+4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok I prefer to write L(y) as Y(s)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[L(y)(s^21)6=10/s^2+4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it should be : \[Y(s)(s^21)={10 \over s^2+4} +6\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you divide each side by s^21 and then look up the transform on a table?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0=>6s^2+34 = Y{s^2  1}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im confused on where you got that thinker

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0= \[Y(s)={6s^2+34 \over s^2+4} . {1 \over s^2 1}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry :) missed the denominator :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you follwoing Scotty?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now i guess u may use partial fractions to solve further

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01 sec I think so im writing it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take your time.. I will be right back

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try a way to write it back in time domain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yep I got it, you were adding 6 into there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can I look up the laplace transform inverse for each and then combine them?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess its possible when there's addition there..here we have multiplication of terms...can u use partial fractions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Forgot how to do those, you're talking about breaking it up right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take , say, (A/s^ + 4)+(b/s^2 1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry it is (A/s^2 + 4)+(b/s^2 1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0mm ok I got it now. Thanks guys... I'm sure I'm gonna post another one here in a min lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think there is something wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no I just ran what we had through my solver and it came up with the correct answer...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I mean the partial fractions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats that?? u know it was 2 years back i studies Laplace transforms :):)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh well the laplace transform before you get to the fractions are correct :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0omg!! did i forget solving these?? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if that's all you want, then it's ok.. but if you want to fin the final solution for the differential equation by yourself, then you need to do the partial fractions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the point is that you want to write the expression we have for Y(s) in a form that is easy to be transformed back to time domain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I didn't learn the notation in form of Y(s) which seems to be the way most people learn it. Very annoying.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0was my suggestion of no help ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No you helped thinker. Thank you :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it doesn't matter what notation you use as long as you understand it.
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