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anonymous

  • 5 years ago

the velocity of a particle moving along he x-axis for time t(greater than or equal to)0 is given by v(t)=sin t m/sec. .......

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  1. anonymous
    • 5 years ago
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    what is the particles displacement from t=0 to t=3Pi/2 seconds?

  2. anonymous
    • 5 years ago
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    it is the integral of sint from t=0 to t=3pi/2

  3. anonymous
    • 5 years ago
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    let s be the displacement, then \[s = \int\limits_{0}^{3\pi/2}\sin t dt= - \cos t _{0}^{3\pi/2}=-(0-1)= 1 m\]

  4. anonymous
    • 5 years ago
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    oh wow! Thank you so much! math is just not my thing even though we went over these since the beginnign of time!

  5. anonymous
    • 5 years ago
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    you're welocme :) is this a course in calculus?

  6. anonymous
    • 5 years ago
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    yes. it's ap calculus at my high school. but honestly my teacher teaches it way too fast because he is obsessed with us passing the ap exam. i think he would be better off teaching at a college level.

  7. anonymous
    • 5 years ago
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    what would the distance the particle traveled during the time interval be?

  8. anonymous
    • 5 years ago
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    do you first know the difference between the displacement and distance?!

  9. anonymous
    • 5 years ago
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    yes displacement is like the amount you have taken overall. say your were at 9 than you took 3 steps left your displacement would be 12, right?

  10. anonymous
    • 5 years ago
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    let's assume you were is position (in the number line) 2 and then you move two steps to the right and then 1 step to the left..so you're now in position 3. okay?

  11. anonymous
    • 5 years ago
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    your displacement in this case is l3-2l=1

  12. anonymous
    • 5 years ago
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    so it is just where you are. not how many steps you have taken...

  13. anonymous
    • 5 years ago
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    but the total distance you traveled is 3, which is 2 right steps and 1 left step

  14. anonymous
    • 5 years ago
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    right ok. got it. thank you. are you like a math major or professor or just a math super genious?

  15. anonymous
    • 5 years ago
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    lol none of them :P

  16. anonymous
    • 5 years ago
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    than what are you?

  17. anonymous
    • 5 years ago
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    if you notice the displacement can be calculated by taking the what the distance you walk to the right minus the distance you walk to the left..( which is 2 -1 =1) while the total distance is just the sum of them (2+1=3)

  18. anonymous
    • 5 years ago
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    a human being I guess

  19. anonymous
    • 5 years ago
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    oh ok... you cant be in high school...to know all that..

  20. anonymous
    • 5 years ago
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    I am a university student.

  21. anonymous
    • 5 years ago
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    hmmm. well. i can not be positive but i'm coming to the conlusion that you are smart. at least when it comes to math. :)

  22. anonymous
    • 5 years ago
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    haha that could be right

  23. anonymous
    • 5 years ago
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    lol. well even though i am so not done with my math work and need tons more help, i must go to my next class because the bell rang... can not wait until this summer to start college so that i can pick my own times to go to school! lol. Thanks for all your help. it wont be long before i am back on though :)

  24. anonymous
    • 5 years ago
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    Have fun :) I miss high school by the way!!

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