anonymous 5 years ago Will someone please explain to me how to work these differentiation logarithmic functions? :(

What particular issues are you having?

i.e., do you have a specific problem you can show that you're having trouble with?

3. anonymous

Sure :D $dy/dx=x/(1+x^2)$ and I'm supposed to solve that by separating and integrating i believe, using the ln and then "e"-ing both sides to get rid of it, but I don't understand how!! Thank you! :)

Hm. Ok, I don't have time to do the entire thing, but basically the starting point is the fact that using ln you can turn a division into a subtraction. So: $\ln \frac{a}{b} = \ln a - \ln b$ You can use that to do: $\ln \frac{dy}{dx} = \ln \frac{x}{1 + x^2}$ $\ln \frac{dy}{dx} = \ln x - \ln(1 + x^2)$ Then you can integrate the two sides. Does that help?

5. anonymous

Yes (: Thank you