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anonymous
 5 years ago
Finding the derivative...
anonymous
 5 years ago
Finding the derivative...

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0h(x)=\[\int\limits_{sinx}^{1}\ln(t^2)dt\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need your help Sapph! :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you want the derivative of the integral or the integral itself?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Umm.. I'm not sure.. What's the difference?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we just need the derivative i believe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think it's asking about the derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, it's the derivative it's asking for.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0using the Fundamental theorem of calculus: \[d/dt \int\limits\limits_{\sin x}^{1} \ln (t^2) dt =  \cos x . \ln(\sin^2 x)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you sort of explain this...?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok here is a general formula: \[d/dx \int\limits_{g(x)}^{h(x)}f(t) dt = h'(x) f(h(x))  g'(x) f(g(x))\] I hope that does not complicate it more

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I suck at explaining things :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hm.. So it's sort of like the product rule?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm not really.. you just take the derivative of the upper border multiplied by the function after substituting in t minus the same thing with lower border

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright well that makes sense :) Thank you :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm trying to work this out myself.. And well.. I can't seem to get the answer. For the first part I get 0 times f(1)... minus cosx.. How do you get ln?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's the same ln in the integral, I just put sinx in the place of t
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