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anonymous
 5 years ago
can anyone define definite and indefinite integrals???
anonymous
 5 years ago
can anyone define definite and indefinite integrals???

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0definite integrals are integrals that have bounds associated with them so that the answers you receive have a defininte value. indefinite integrals are boundless and therefore have no definite value unless given an initial condition to anchor it to the graph

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok...now, can you tone that down a bit?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0not really, thats really the simplest explanation I got :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0definite means it has a specific and determinable value because it fits inside a box. indefinite means that it cannot be measured; so we attach a generic "+C" to it until we can define it better

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0definite= whats the area of a sealed box? indefinite = whats the area of a box that has no top bottom or sides?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. i understand that now thank you. but i really do not understand how it works. if i gave a problem could you explain it a little?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{2}\sqrt{x1}\times dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, and how do we tell if a problem is definite or indefinite?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if it is definite that elongates "s" will have numbers around it; if its indefinite, then the "s" will be bare naked.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so the problem above is definite

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it is..... it is bounded by the x axis, the x = 1 line the x = 2 line and the y = sqrt(x1) line; so its completely boxed in :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. i think im getting it. so to solve the problem, what would you do from there?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you would have to integrate that sqrt(x1) part; which in this cqse is quite simple....they give you easy ones to begin with to build your confidence so later down the road they can shatter it to pieces :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol. they will have nothing to shatter because i have yet to build any confidence in this subject...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think you're missing an x in this question..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if youve done derivatives, then integrating is suiting it back up. Derivatives dress down a function; and integrals suit it back up.... thats about it...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh yes i am! sorry. its before \[\sqrt{x1}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we will define u = x1 ; therefore; du=1 we will also rewrite the expresion as an exponent to make life easier for us

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0du = dx (x1)^(1/2) dx > u^(1/2) du add 1 to the exponent , and divide by the exponent+1 u^(1/2 + 2/2)  1/2 + 2/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02u^(3/2) 2(x1)^(3/2)  =  is our F(x) suited up function, 3 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your already explaining it better than my teacher!:)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Now to determine the answer to our problem we do this: F(2)  F(1) and that equals the answer we seek. and thanx :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02(21)^(3/2)  2(11)^(3/2)  3 2(1)^(3/2)  2(0)^(3/2)  3 2(1)  2(0) 20 2  =  =  3 3 3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0didnt quite line up there did it :) 2/3 is the answer I get

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you!!! this makes much more sense! are you a teacher?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0no im not, im just old and smelly :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hehe :D i am sure your not. but really, i thought i was a lost cause...but now there is hope! maybe..i need to try one on my own..
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