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anonymous
 5 years ago
I need to solve this, then graph it.
y=x^6x+8
anonymous
 5 years ago
I need to solve this, then graph it. y=x^6x+8

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^26x+8 or x^6x+8 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I asked if \[x ^{2}6x+8\] or \[x ^{6x}+8\] ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im trying to figure out how to solve that parabola in standard form

radar
 5 years ago
Best ResponseYou've already chosen the best response.0y= (x4)(x2) those are your zero points for y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And to graph it , you may need vertex ,for f(x)=ax^2+bx+c , vertex is (b/2a,f(b/2a))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you should write your equation in a complete square form, that's: \[y=(x3)^21\] the vertex is (3,0)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok how to solve : to find x the x interecepts and y intercept

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x intercepts and y intercepts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To find x intercepts , suppose y=0 , y=(x4)(x2) so (x4)(x2)=0 , x intercepts are 4 and 2 To find y intercept , plug in 0 to x so 4*2=8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to find yint plug x=0, and to find xint plug y=0. you will get yint (0,8).. and two xint (4,0), (2,0)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I cannot do that because x and x sqaured arent like terms?
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