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differentiate

set it equal to zero and solve for x

but i have to solve it using 'completing the squares'

so no calc?

wat do u mean by that?

oops i left something out

lol oops that 4th step should be
=a(x+b/[2a])^2-b^2/[4a]
the vertex is (-b/[2a],-b^2/[4a])

this one?

ya i dont get it

nop

we are learning 'cpmpleting the sqaures'

ax^2 + bx +c = 0
lets solve for any quadratic equation by going thru this setup..

ya

hmm..we divide the middle term by 2 ...then square it and stuff...yup

i dont know

I think you do :)
tell me:
does (x^2 +6x +3) = (x^2 +6x +3 +0) ??

ya

s?

i get wat u r saying

cool...
so we do this:
(x^2 +6x +9) -9 +3 in order to "complete" the square right?

ya

so hw do we apply that to this q:

yup

now... do you see the answer or can i do my magic and show you whats right before your eyes :)

ya

does that make sense for you?