anonymous
  • anonymous
the parabola has a y-intercept of 5 anf contains the point (2,-3) and (-1,12). what are the coordinates of the vertex?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
(0,5) (2,-3) (-1,12) right?
anonymous
  • anonymous
yes
amistre64
  • amistre64
0a + 0b + 5 = 5 4a +2b + 5 = -3 a -b +5 = 12 ; a = 12-5 +b ---------------------------- a = 7 +b ---------------- 4(7+b) +2b + 5 = -3 28 +4b +2b = -8 6b = -36 b = -6 c = 5 ----------------------- a = 12-5 +b; a = 12-5-6 a = 1 -------------------------- y =x^2 -6x +5 is your equation for hese points

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
the vertex is at -b/2a 6/2 = 3 the vertex is at (3,y) y = (3)^2-6(3) +5 y = 9 -18 +5 y = 14 -18 y = -4 vartex is at (3,-4) if I did it right ;)
amistre64
  • amistre64
you agree or disagree :)
anonymous
  • anonymous
thanx ..that is the rite answer i agree
amistre64
  • amistre64
yay!! if you ever wanna know "how" its the right answer... I can do that too :)
anonymous
  • anonymous
ya..i dont get the first few steps
amistre64
  • amistre64
we know that these three points are not in a straight line, so that only leaves a parabola as an answer that we can actually get.
amistre64
  • amistre64
a parabola usually is of the form: ax^2 +bx + c = y ; and you normally try to figure out the "x" and "y" values...but they already give you those right?
anonymous
  • anonymous
yup
amistre64
  • amistre64
so we get the first 3 equations: a(0)^2 +b(0) +c = 5 ; (0,5).. c = 5 naturally
amistre64
  • amistre64
the "variables" we are trying to get them to have on common are the a, b, and c parts so this is almost a backwards solution lol
amistre64
  • amistre64
a(2)^2 + b(2) + c = -3 4a +2b +5 = -3 4a +2b = -8 right?
anonymous
  • anonymous
yup..
amistre64
  • amistre64
a(-1)^2 +b(-1) + c = 12 ; (-1,12) a -b +5 = 12 a - b = 12 - 5 a = 7 +b right?
anonymous
  • anonymous
oh..i get it!!
amistre64
  • amistre64
4a +2b = -8 ; so plub if our "value" for "a" 4(7+b) +2b = -8 28 +4b +2b = -8 6b = -36 b = -6 :)
amistre64
  • amistre64
a = 7+b so... a = 7 -6 = 1 our quad equation becomes: x^2 -6x +5 = y :)
anonymous
  • anonymous
thanx a lot friend..
amistre64
  • amistre64
youre welcome :)
anonymous
  • anonymous
would u like to look through the other question i posted too..
amistre64
  • amistre64
if I can find it lol
anonymous
  • anonymous
okay

Looking for something else?

Not the answer you are looking for? Search for more explanations.