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anonymous
 5 years ago
the parabola has a yintercept of 5 anf contains the point (2,3) and (1,12). what are the coordinates of the vertex?
anonymous
 5 years ago
the parabola has a yintercept of 5 anf contains the point (2,3) and (1,12). what are the coordinates of the vertex?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(0,5) (2,3) (1,12) right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.00a + 0b + 5 = 5 4a +2b + 5 = 3 a b +5 = 12 ; a = 125 +b  a = 7 +b  4(7+b) +2b + 5 = 3 28 +4b +2b = 8 6b = 36 b = 6 c = 5  a = 125 +b; a = 1256 a = 1  y =x^2 6x +5 is your equation for hese points

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the vertex is at b/2a 6/2 = 3 the vertex is at (3,y) y = (3)^26(3) +5 y = 9 18 +5 y = 14 18 y = 4 vartex is at (3,4) if I did it right ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you agree or disagree :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanx ..that is the rite answer i agree

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yay!! if you ever wanna know "how" its the right answer... I can do that too :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya..i dont get the first few steps

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we know that these three points are not in a straight line, so that only leaves a parabola as an answer that we can actually get.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a parabola usually is of the form: ax^2 +bx + c = y ; and you normally try to figure out the "x" and "y" values...but they already give you those right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so we get the first 3 equations: a(0)^2 +b(0) +c = 5 ; (0,5).. c = 5 naturally

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the "variables" we are trying to get them to have on common are the a, b, and c parts so this is almost a backwards solution lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a(2)^2 + b(2) + c = 3 4a +2b +5 = 3 4a +2b = 8 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a(1)^2 +b(1) + c = 12 ; (1,12) a b +5 = 12 a  b = 12  5 a = 7 +b right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04a +2b = 8 ; so plub if our "value" for "a" 4(7+b) +2b = 8 28 +4b +2b = 8 6b = 36 b = 6 :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a = 7+b so... a = 7 6 = 1 our quad equation becomes: x^2 6x +5 = y :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would u like to look through the other question i posted too..
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