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anonymous
 5 years ago
how do you solve this x1=x+1
 
2x+1 x1
anonymous
 5 years ago
how do you solve this x1=x+1   2x+1 x1

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radar
 5 years ago
Best ResponseYou've already chosen the best response.0I think you end up with (x+1)/(2x+1) providing the equation is what I think it is

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I am assuming it is: (x1)/(2x+1) = (x+1)/(x1)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0O.K. The (x1) can be eliminated.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0They "cancel" but I can't remember the rule. I'm thinking.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The (x1)'s can't be eliminated if you have an = sign between the fractions. If it is a multiplication problem, then they could be eliminated.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need to cross multiply. (x  1)(x 1) = (2x + 1)(x + 1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^2  2x + 1 = 2x^2 + 3x + 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0make this equal to 0 0 = x^2 + 5x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Factor 0 = x(x + 5) So x = 0 or x = 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks i can see exactly were you got every number from ill do the next one and see if i understood it

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I am trying to prove those answers, when I subsstitute the 5 it does not check out. Where am I going wrong?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0(51)/(2(5)+1)=(5+1)/(51) 6/9 = 4/6 Unh unh Something is wrong with the solution.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Never mind I didn't reduce!! lol
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