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anonymous

  • 5 years ago

how do you solve this x-1=x+1 --- ---- 2x+1 x-1

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  1. radar
    • 5 years ago
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    I think you end up with (x+1)/(2x+1) providing the equation is what I think it is

  2. radar
    • 5 years ago
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    I am assuming it is: (x-1)/(2x+1) = (x+1)/(x-1)

  3. anonymous
    • 5 years ago
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    yes

  4. radar
    • 5 years ago
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    O.K. The (x-1) can be eliminated.

  5. radar
    • 5 years ago
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    They "cancel" but I can't remember the rule. I'm thinking.

  6. anonymous
    • 5 years ago
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    The (x-1)'s can't be eliminated if you have an = sign between the fractions. If it is a multiplication problem, then they could be eliminated.

  7. radar
    • 5 years ago
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    ooops

  8. anonymous
    • 5 years ago
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    You need to cross multiply. (x - 1)(x -1) = (2x + 1)(x + 1)

  9. anonymous
    • 5 years ago
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    x^2 - 2x + 1 = 2x^2 + 3x + 1

  10. anonymous
    • 5 years ago
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    make this equal to 0 0 = x^2 + 5x

  11. anonymous
    • 5 years ago
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    Factor 0 = x(x + 5) So x = 0 or x = -5

  12. anonymous
    • 5 years ago
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    thanks i can see exactly were you got every number from ill do the next one and see if i understood it

  13. radar
    • 5 years ago
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    I am trying to prove those answers, when I subsstitute the -5 it does not check out. Where am I going wrong?

  14. radar
    • 5 years ago
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    (-5-1)/(2(-5)+1)=(-5+1)/(-5-1) -6/-9 = -4/-6 Unh unh Something is wrong with the solution.

  15. radar
    • 5 years ago
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    Never mind I didn't reduce!! lol

  16. radar
    • 5 years ago
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    2/3=2/3

  17. radar
    • 5 years ago
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    I had a senior moment!

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spraguer (Moderator)
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