A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
What are the vertical asymptotes, horizontal asymptotes, slant asymptotes, and the holes of this equation:
(x^3+5x^2)/(x^225)
anonymous
 5 years ago
What are the vertical asymptotes, horizontal asymptotes, slant asymptotes, and the holes of this equation: (x^3+5x^2)/(x^225)

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is no horizontal asymptotes if numerator's degree greater than denominator. You should make Polynomial Long Division to have slant asymtotes. to find holes and vertical asymtotes make denominator=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. so what are the holes and vertical asymptotes because i am not sure if i did it right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Vertical asymptotes is like Hakanka said, set the denominator equal to zero and solve. Holes come from factoring both the numerator and the denominator and cancelling a common factor...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok but im not sure if i did it correctly so can you tell me what the holes and vertical asymptotes are so i can see if i am correct...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^225=0\] gives x=5,5 when you factor everything you get \[x(x+5)(x+5)/((x+5)(x5))\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am sorry for giving wrong info ,Yes, Holes come from factoring both the numerator and the denominator thanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so then what is the slant asymptote and the vertical asymptote?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The vertical asymptote is at x=5, technically it would be at 5 as well, since those are both answers we get when the denominator is set to zero, but there is a hole in the graph there instead. Slant asymptote comes from dividing the denominator into the numerator.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, but then what are the holes?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is a hole at x=5 because the factor (x+5) appears both in the numerator and the denominator.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so tell me if i am right: holes=5,5 vertical asymptote= 5,5 slant= ?? i dont know. please tell me horizontal asymptote= 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok I want to first say one thing, I factor wrong because I wrote the wrong number down, but it doesn't change any of the answers. Should have factored like \[x^2(x+5)/((x+5)(x5))\] For some dumb reason I wrote 25 instead of 5 down. But anyway, vertical asymptote is just x=5 you also get x=5 when you solve, but when you check for holes, you get a hole at 5 which overrides the asymptote. There is no horizontal asymptote.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. so what is the slant??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When you take the denominator and divide it into the numerator you get x+5 with a remainder, which doesn't matter so the slant asymptote is x+5. If you were to graph this function, you would see all of these asymptotes in action :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so once again: the vertical asymptote= 5 the holes = 5 is that right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, one more question. is the slant x5 or x+5 because i think it is x5 but im not sure

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's x+5, x5 would go through the graph. x+5 is what you get when you divide correctly :) and doesn't cross the graph.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.