help how do u solve sqrt(x)+sqrt(2x)=1

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help how do u solve sqrt(x)+sqrt(2x)=1

Mathematics
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3-2sqrt(2)
is it possible to explain or show me how you got this
yes, first square both sides

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add them together you get (3+2sqrt(2))x=1
this is tricky, you realize that if you multiply by the complement, you get 9-8 which equals 1
oh ok i understand it now i know ho to do the ones with one sqrt but wasnt sure how to do it with two sqrt's thanks
sometimes it takes just a little flash of insight
wait i just got lost were did you get the 3 from
\[(\sqrt{x}+\sqrt{2x})^{2}\]
that should result in: 3x plusminus (2x)2^1/2. But he omitted squaring the other side getting a 1
and the equating that ugly thing to 1 and solving, so far I haven't seen a solution.
well the solution is 3-2\[\sqrt{2}\]
i mean t 3-2sqrt(2)
but i dont know how he got that i got lost after i looked back again
see, the thing is (3+2sqrt(2))(3-2sqrt(2))=(3)^2-(2sqrt(2))^2
which is 9-8=1
the COMPLEMENT of (3+2sqrt(2)) is (3-2sqrt(2)) b/c that is like squaring both elements.
So your using + root, a - root. Is that a fair statement?
It does check out, in a baffling sort of way.

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