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anonymous

  • 5 years ago

help how do u solve sqrt(x)+sqrt(2x)=1

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  1. anonymous
    • 5 years ago
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    3-2sqrt(2)

  2. anonymous
    • 5 years ago
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    is it possible to explain or show me how you got this

  3. anonymous
    • 5 years ago
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    yes, first square both sides

  4. anonymous
    • 5 years ago
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    add them together you get (3+2sqrt(2))x=1

  5. anonymous
    • 5 years ago
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    this is tricky, you realize that if you multiply by the complement, you get 9-8 which equals 1

  6. anonymous
    • 5 years ago
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    oh ok i understand it now i know ho to do the ones with one sqrt but wasnt sure how to do it with two sqrt's thanks

  7. anonymous
    • 5 years ago
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    sometimes it takes just a little flash of insight

  8. anonymous
    • 5 years ago
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    wait i just got lost were did you get the 3 from

  9. radar
    • 5 years ago
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    \[(\sqrt{x}+\sqrt{2x})^{2}\]

  10. radar
    • 5 years ago
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    that should result in: 3x plusminus (2x)2^1/2. But he omitted squaring the other side getting a 1

  11. radar
    • 5 years ago
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    and the equating that ugly thing to 1 and solving, so far I haven't seen a solution.

  12. anonymous
    • 5 years ago
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    well the solution is 3-2\[\sqrt{2}\]

  13. anonymous
    • 5 years ago
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    i mean t 3-2sqrt(2)

  14. anonymous
    • 5 years ago
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    but i dont know how he got that i got lost after i looked back again

  15. anonymous
    • 5 years ago
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    see, the thing is (3+2sqrt(2))(3-2sqrt(2))=(3)^2-(2sqrt(2))^2

  16. anonymous
    • 5 years ago
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    which is 9-8=1

  17. anonymous
    • 5 years ago
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    the COMPLEMENT of (3+2sqrt(2)) is (3-2sqrt(2)) b/c that is like squaring both elements.

  18. radar
    • 5 years ago
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    So your using + root, a - root. Is that a fair statement?

  19. radar
    • 5 years ago
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    It does check out, in a baffling sort of way.

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spraguer (Moderator)
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