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anonymous

  • 5 years ago

find limit: lim sqrt(x)ln(x) x>0

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  1. anonymous
    • 5 years ago
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    0

  2. anonymous
    • 5 years ago
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    this requires calculus first, manipulate so it becomes lim(x>0) ln(x)/(sqrt(x))^(-1) then do L'Hopital's rule and take the derivative of top and bottom. you get lim(x>0) (1/x)/(-1/2x^(-3/2))

  3. anonymous
    • 5 years ago
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    ugly, but then simplify it to get lim(x>0) -2sqrt(x) that will equal 0

  4. anonymous
    • 5 years ago
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    On first try you get 0 times negative infinity. (Write that down you will see again lim x to zero of ln 0 is negative infinitiy.) However that is indeterminate form: apply l'hopital, try again.

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