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anonymous

  • 5 years ago

a. Suppose two animals are in a race. Choose the two animals and calculate the speed of each animal in yards per second. my answers: Cheetah 70 mph 70 miles x 1 hour x 1760 yds = 34 yds/sec 1 hour 3600 sec 1 mile Lion 50 Mph 50 mph x 1 hour x 1760 yds = 24 yds/sec 1 hour 3600 1 mile b. Decide how much of a head start (in yards) the faster animal offers the slower animal. For each animal, write an equation relating distance from the starting line to time. Please help me write the equation, i don't know how. i think i need to use the form d=r*h but i don't know what numbers to plug in

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  1. anonymous
    • 5 years ago
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    Here is the answer to A: Pick two animals to be in a race and answer the following questions. a. Suppose two animals are in a race. Choose the two animals and calculate the speed of each animal in yards per second. Cheetah 70 mph 70 miles x 1 hour x 1760 yds = 34.2 yds/sec! AND B! Do you understand now? 1 hour 3600 sec 1 mile Fox 42 Mph 42 miles x 1 hour x 1760 yds = 20.5 yds/sec 1 hour 3600 1 mile b. Decide how much of a head start (in yards) the faster animal offers the slower animal. For each animal, write an equation relating distance from the starting line to time. (This is where I am having trouble.. these are my answers but they just doesn't seem right! I have to graph them and the graph seems weird.) Fox 348.5y=20.5x Cheetah y=34.2x

  2. anonymous
    • 5 years ago
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    i saw that answer on an algebra website, but it still doesn't help me :/ i still don't know how to write the equation

  3. anonymous
    • 5 years ago
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    Well im a part of that website, anyway think of it like this! What is the main message of your question?!!! Tell me the main message of what the problem is asking

  4. anonymous
    • 5 years ago
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    the cheetah started at 0 yards at a speed of 34yd/sec and gave the lion a 10 second head start with the lion going at a speed of 24yd/sec. but how do i write two equations for this?

  5. anonymous
    • 5 years ago
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    Good, The proper way of doing this is by... Taking each speed of the animal and timsing it by the other speeds.... Thats one way

  6. anonymous
    • 5 years ago
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    what form do i put it in? i have to graph both equations

  7. anonymous
    • 5 years ago
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    What kind of graph? And form it by the formilar I gave for each animal

  8. anonymous
    • 5 years ago
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    in my book it says graph the two linear quations on the same coordinate plane

  9. anonymous
    • 5 years ago
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    im so confused i was trying to figure this out all day

  10. anonymous
    • 5 years ago
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    Well there you go, Fox 348.5y=20.5x Cheetah y=34.2x . Yea math is truly insane, anyway that is a two liner kind the one I gave... wait let me solve this on paper!

  11. anonymous
    • 5 years ago
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    what would the lion equation be? i know the cheetah one

  12. anonymous
    • 5 years ago
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    Which want you want?

  13. anonymous
    • 5 years ago
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    the lion one

  14. anonymous
    • 5 years ago
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    i have another question too

  15. anonymous
    • 5 years ago
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    ok let me get it....

  16. anonymous
    • 5 years ago
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    how long will it take the cheetah to overtake the lion? and how many yards from the starting line are the animals when the cheetah overtakes the lion?

  17. anonymous
    • 5 years ago
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    ok well for the lion it is 348.5y=20.5x Is what i got i think it is right... to find out how the cheetah to overtake the lion subtract the lion and cheetah. I dont know what you mean for question number 2

  18. anonymous
    • 5 years ago
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    where did the 348.5 come from?

  19. anonymous
    • 5 years ago
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    well, thanks for helping me :) , i'll try to figure out the rest on my own. byee

  20. anonymous
    • 5 years ago
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    No problem! =) hope you get a good grade! GOOD LUCK

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