solve for (a+bi)^3 dealing with complex numbers

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solve for (a+bi)^3 dealing with complex numbers

Mathematics
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(a+bi)(a+bi)(a+bi) do it like normally; the i's are just another variable in this case. when you get to the end....anything that has an i^2 is multiplied by -1
i think the problem that i have is that they are not numbers so it messes me up but i have to foil all this right
yeah foil it , and dont be intimidated by that i..... own it :)

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(a+bi)(a+bi) (a^2 +2abi +(bi)^2) --------------------- (a+bi)(a^2 +2abi +(bi)^2) a^3 +3a^2bi +3a(bi)^2 + (bi)^3 .... if I did it right :)
a^3 +3a^2b(i) +3ab^2(i^2) +b^3(i)(i^2) a^3 +3a^2b(i) -3ab^2 -b^3(i) a^3 -3ab^2 +3a^2b(i) -b^3(i) looks about right
but if im wrong, let me know ;)
well im not exactly sure how to enter in cause it gives (a+bi)^3=box+box i
I think I see a solution to the problem :)
[ a(a^2 +3b^2) ] box1 + [ b(3a^2 - b^2) ] box2 [i]
ok ill see thanks

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