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anonymous
 5 years ago
What are the vertical asymptotes, horizontal asymptotes, slant asymptotes, and the holes of this equation:
(x^29x+20)/(2x^28x)
anonymous
 5 years ago
What are the vertical asymptotes, horizontal asymptotes, slant asymptotes, and the holes of this equation: (x^29x+20)/(2x^28x)

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0since the bottom and top degrees are the same; the HA is the qoutient of the top leading coefficient and the bottom leading coefficint HA = 1/2 Vas are where your bottom goes to zero; so factor it out and check for roots

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a hole is where the bottom gets canceled out by a like facotr on the top, so factor your top as well

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(x5)(x4)  2x(x4)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0horizontal asymp are the most fun

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0there is a hole at x=4; and a VA at x = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure that the horizontal asymptote is 1/2 because i thought it was 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im sure; if its what you wrote up top then: x^29x+20 1+.....  =  = 1/2 2x^28x 2+.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you take the limit as x goes to infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0divide top and bottom by x^2 to clear things up and yeah, you end up with 1/2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0since the degrees are the same you just take the coeiffient of the leading exponent term in the numerator over the coefficent of the leading exponent term in the denominator

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0divide everything by the highest degree variable in the bottom.... anything left stuck with an x in its bottom gets thrown in the trash

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok and what is the slant?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0there is no slantl the slant is what happens the degree of the top is heavier than the degree of the bottom

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0(x^3+1)/(x^2+1) would have a slant since the degree of the top is one more than the degree of the bottm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the slant is when you do long division. so what is the slant?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0its a line as that the curve gets closer to as x gets closer to infinity

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0there.....is.....NO .....slant.......to .....your.....problem.....
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