Does anyone know the integral of -e^{-2y}

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Does anyone know the integral of -e^{-2y}

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

i think I can do that....
(1/2)e^(-2y)
[S] -e^-2y dy (1/2) [S] -2 e^-2y dy e^-2y ----- is what I get if I did it right :) 2

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

We are having a dispute as to whether or not the 2y stays negative
+C ....dont forget the +C lol
arrrgh
yeah thats right....i got it....go me.... its not my birthday but it was at somepoint....uhhunh
i h8 this someday i'll start writing alculus and someone'll go "+C!!!"
LOL
So the integral of e^{-x) = -e^{-x}+c doesnt e^{-2y} end up -(1/2)e^{-2y}+c? Or am I wrong about the -e?
thats exponential shouldnt change so thats correct, but it is divided by constant -2 so it works out to be positive

Not the answer you are looking for?

Search for more explanations.

Ask your own question