anonymous
  • anonymous
Does anyone know the integral of -e^{-2y}
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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amistre64
  • amistre64
i think I can do that....
anonymous
  • anonymous
(1/2)e^(-2y)
amistre64
  • amistre64
[S] -e^-2y dy (1/2) [S] -2 e^-2y dy e^-2y ----- is what I get if I did it right :) 2

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anonymous
  • anonymous
We are having a dispute as to whether or not the 2y stays negative
amistre64
  • amistre64
+C ....dont forget the +C lol
anonymous
  • anonymous
arrrgh
amistre64
  • amistre64
yeah thats right....i got it....go me.... its not my birthday but it was at somepoint....uhhunh
anonymous
  • anonymous
i h8 this someday i'll start writing alculus and someone'll go "+C!!!"
amistre64
  • amistre64
LOL
anonymous
  • anonymous
So the integral of e^{-x) = -e^{-x}+c doesnt e^{-2y} end up -(1/2)e^{-2y}+c? Or am I wrong about the -e?
anonymous
  • anonymous
thats exponential shouldnt change so thats correct, but it is divided by constant -2 so it works out to be positive

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