A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
can anyone tell me if the answer is 1292 to this problem?
A rock is launched from the cannon. After 1 second, the rock is 186 feet in the air. After 2 seconds, the rock is 344 feet in the air. Using quadratic functions, find the height, in feet, of the rock after 8 seconds in the air.
anonymous
 5 years ago
can anyone tell me if the answer is 1292 to this problem? A rock is launched from the cannon. After 1 second, the rock is 186 feet in the air. After 2 seconds, the rock is 344 feet in the air. Using quadratic functions, find the height, in feet, of the rock after 8 seconds in the air.

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If we let f(t) = at^2+bt+c = 0 and we assume that c = 0 because the cannon fires from the ground then f(1) = a(1)^2+b(1)+0 = 186 and f(2) = a(2)^2+b(2)+0 = 344. Solving for a and b therefore yields a=14 and b=200 so that f(8) = 14(8)^2+200(8)+0=708. Hence, the rocket is 704 feet high at t = 8 seconds. Does this make any sense to you?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.