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anonymous
 5 years ago
Write the trigonometric expression in terms of sine and cosine, and then simplify.
tan(theta) // sec(theta)  cos(theta)
anonymous
 5 years ago
Write the trigonometric expression in terms of sine and cosine, and then simplify. tan(theta) // sec(theta)  cos(theta)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tan = sin/cos sec = 1/cos

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0nite lol...and you too star :) librarys closing up on me...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you literally in a library?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks a lot amistre :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can plug in the given suzi has given you and you'll get the following:\[\tan \theta /(\sec \theta  \cos \theta) = (\sin \theta/\cos \theta)/[(1\cos^2 \theta)/\cos \theta]\] now simplify : \[= (\cos \theta \sin \theta)/(\cos \theta \sin^2 \theta)\] \[= 1/\sin \theta\] ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0good night amistre :)
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