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anonymous

  • 5 years ago

Write the trigonometric expression in terms of sine and cosine, and then simplify. tan(theta) // sec(theta) - cos(theta)

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  1. anonymous
    • 5 years ago
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    tan = sin/cos sec = 1/cos

  2. amistre64
    • 5 years ago
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    nite lol...and you too star :) librarys closing up on me...

  3. anonymous
    • 5 years ago
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    Are you literally in a library?

  4. anonymous
    • 5 years ago
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    Thanks a lot amistre :)

  5. anonymous
    • 5 years ago
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    You can plug in the given suzi has given you and you'll get the following:\[\tan \theta /(\sec \theta - \cos \theta) = (\sin \theta/\cos \theta)/[(1-\cos^2 \theta)/\cos \theta]\] now simplify : \[= (\cos \theta \sin \theta)/(\cos \theta \sin^2 \theta)\] \[= 1/\sin \theta\] ^_^

  6. anonymous
    • 5 years ago
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    good night amistre :)

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