anonymous
  • anonymous
Simplify the trigonometric expression. cos[x]/ tan[x] + sex[x]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Where is the sec(x) in the denominator or by itself
anonymous
  • anonymous
by itself
anonymous
  • anonymous
cosx --- + sec x tanx cosx 1 ---- + ---- sinx sinx ---- cos x cosx divided by sinx/cosx is actually cosx times cosx/sinx cos^2x 1 ------ + ------ sinx sinx cos^2x + 1 ---------- sinx That may be as far as you can take it...

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anonymous
  • anonymous
bleh, that's wrong said loco :( but good that you've tried too blex ^_^
anonymous
  • anonymous
thanks blex :)
anonymous
  • anonymous
The last step blex did is wrong. cos^2 is not equal to cos^2+1. Cos/Tan + Sec Cos^2/Sin + Sec... Expanding the tangent into its components. (Sin^2 - 1)/Sin + Sec... Using the identity sin^2 + cos^2 = 1. Sin^2/Sin - 1/Sin + Sec... Separating out the numerator of the fraction. Sin - Sec + Sec... The first term has a sin that cancels, the second term is just secant. Sin... Both the secants cancel and you're left with just sin.

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