anonymous
  • anonymous
Simplify the trigonometric expression. cos[x]/ tan[x] + sex[x]
Mathematics
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anonymous
  • anonymous
Simplify the trigonometric expression. cos[x]/ tan[x] + sex[x]
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Where is the sec(x) in the denominator or by itself
anonymous
  • anonymous
by itself
anonymous
  • anonymous
cosx --- + sec x tanx cosx 1 ---- + ---- sinx sinx ---- cos x cosx divided by sinx/cosx is actually cosx times cosx/sinx cos^2x 1 ------ + ------ sinx sinx cos^2x + 1 ---------- sinx That may be as far as you can take it...

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anonymous
  • anonymous
bleh, that's wrong said loco :( but good that you've tried too blex ^_^
anonymous
  • anonymous
thanks blex :)
anonymous
  • anonymous
The last step blex did is wrong. cos^2 is not equal to cos^2+1. Cos/Tan + Sec Cos^2/Sin + Sec... Expanding the tangent into its components. (Sin^2 - 1)/Sin + Sec... Using the identity sin^2 + cos^2 = 1. Sin^2/Sin - 1/Sin + Sec... Separating out the numerator of the fraction. Sin - Sec + Sec... The first term has a sin that cancels, the second term is just secant. Sin... Both the secants cancel and you're left with just sin.

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