anonymous
  • anonymous
when making a long distance call from a cetain pay phone, the first three minutes of a call cost $2.25. After that, each additional minute or portion of a minute of that call costs $0.30. Using the inequality C is greater than or equal to 2.25+0.30(X-3)where C is the total cost and X is the number of minutes, find the number of minutes one can call long distance for $4.35. Please show the work so i can do it.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
^^please help me on this assignment. Please show the work so i can know how to do it. Thanks
anonymous
  • anonymous
well you already have the equation: C=2.25+0.30(X-3).. that means you can get the cost for known number of minutes and vice versa

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anonymous
  • anonymous
so just substitute for C=4.35 (the cost) to get the number of minutes, that's: 4.35=2.25+0.30(X-3).. just solve the equation for X.
anonymous
  • anonymous
\[4.35=2.25+0.30(X-3) \implies 0.30(X-3)=4.35-2.25\] \[\implies 0.30(X-3)=2.1 \implies X-3=7 \implies X=10\]
anonymous
  • anonymous
10 minutes is the answer you're looking for :)
anonymous
  • anonymous
does that make sense to you?

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