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  • 5 years ago

the second side of a triangle is 5 inches more than the first side. The third side is 12 inches less than the first side. the perimeter of the triangle is 41 inches. Find each of the triangle.

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  1. anonymous
    • 5 years ago
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    assuming x,y and z are the first, second and third side respectively. and using the informations you gave in the question, we can write the following system of equations: \[x=y-5 \rightarrow(1) \] \[x=z+12 \rightarrow (2)\] \[x+y+z=41 \rightarrow(3)\] do you know how to solve such a system of equations?

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