the second side of a triangle is 5 inches more than the first side. The third side is 12 inches less than the first side. the perimeter of the triangle is 41 inches. Find each of the triangle.

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the second side of a triangle is 5 inches more than the first side. The third side is 12 inches less than the first side. the perimeter of the triangle is 41 inches. Find each of the triangle.

Mathematics
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assuming x,y and z are the first, second and third side respectively. and using the informations you gave in the question, we can write the following system of equations: \[x=y-5 \rightarrow(1) \] \[x=z+12 \rightarrow (2)\] \[x+y+z=41 \rightarrow(3)\] do you know how to solve such a system of equations?

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