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anonymous

  • 5 years ago

calculate the gradient

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  1. anonymous
    • 5 years ago
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    \[f(x,y)=\sqrt{36x ^{2}+ 4 y ^{2}}\]

  2. anonymous
    • 5 years ago
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    \[\Delta\f] =? triangle is supposed to be inverted

  3. anonymous
    • 5 years ago
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    \[\Delta f(x,y) =?\]

  4. anonymous
    • 5 years ago
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    diff. f w.r.t. x keeping y as constant Fx= [1/ 2 sqrt(36x^2 + 4y^2) } *72x similarly, diff f w.r.t. y keeping x as constant Fy= [1/ 2sqrt (36x^2 + 4y^2) } * 8y combining these gives us our gradient vector

  5. anonymous
    • 5 years ago
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    and u might have used wrong symbol for gradient ..its inverse triangle

  6. anonymous
    • 5 years ago
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    yes. i got tht. answer confirmed =) yes i had mentioned it above tht there should ve been inverted triangle

  7. anonymous
    • 5 years ago
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    pls fan me ..to keep the help sharing

  8. anonymous
    • 5 years ago
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    ok but b4 that. an imp question.

  9. anonymous
    • 5 years ago
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    sure

  10. anonymous
    • 5 years ago
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    u know directional derivative completely? and Lagrange multiplier too?

  11. anonymous
    • 5 years ago
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    i know the first one..havent touched the latter one yet..

  12. anonymous
    • 5 years ago
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    oh.

  13. anonymous
    • 5 years ago
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    ?

  14. anonymous
    • 5 years ago
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    well the question was requiring Lagrange multiplier

  15. anonymous
    • 5 years ago
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    :(

  16. anonymous
    • 5 years ago
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    so what do i need to do to get ur vote? hahha

  17. anonymous
    • 5 years ago
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    =D answer my next question if needed =P

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spraguer (Moderator)
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