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anonymous
 5 years ago
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 40 m in front of you. Your reaction time before stepping on the brakes is
0.50 s , and the maximum deceleration of your car is 12 m/2^2
How much distance is between you and the deer when you come to a stop?
What is the maximum speed you could have and still not hit the deer?
anonymous
 5 years ago
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 40 m in front of you. Your reaction time before stepping on the brakes is 0.50 s , and the maximum deceleration of your car is 12 m/2^2 How much distance is between you and the deer when you come to a stop? What is the maximum speed you could have and still not hit the deer?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I solved the problem, but I am not so sure about my answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cam i see wat you did?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I first found the time needed for the car to stop, that's when the final velocity is zero. Apply it to the formula: \[v_f=v_i+at \implies 0=2012t \implies t=20/12=1.67\] (since it's decelerating, I took a to be negative)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but we know that the reaction was 0.5 s late so the total time needed is t=1.67+0.5=2.17

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you following so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok I will just write the rest. now we will have to find the distance he is going to drive during this period of time, which is: \[x={v_i}t+0.5at^2\] just direct substitution in the formula, you will get: \[x=20 (2.17)+0.5(12)(2.17)^2=15.15 m\] so the distance he traveles before the car stops is 15.15 meter

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now it's easy to find the distance between the car and the deer, which is 4015.15=24.85 meter

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I dunno if you have the final answers?
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