anonymous
  • anonymous
How do you solve the IVP, y' = y^2 + 2, y(0) = 1
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
It's separable so you have dy/dx=y^2+2. You want to get all the y's together with the dy. So multiple both sides by dx. Then divide both sides by y^2+2. You have 1/(y^2+2)dy=dx. Integrate both sides and plug in initial conditions to solve for the constant of integration

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