anonymous
  • anonymous
I am doing quadratic functions Can someone help me solve this y=-2x^2+11x-12
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Solve it for y = 0? Are you familiar with the quadratic formula?
anonymous
  • anonymous
yes but this is +or - a=-2,b=11 c=-12
anonymous
  • anonymous
I know how to do the formula but have done 10 problems but don't come up with the correct answer

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Those are the correct values for a, b, and c.
anonymous
  • anonymous
\[11+-\sqrt{(11^2-4(-2)(-12)}\]
anonymous
  • anonymous
I have done the numbers in parenthesis first what do you come up with
anonymous
  • anonymous
\(11^2 - 4(-2)(-12) = 25\)
anonymous
  • anonymous
okay that is what I got
anonymous
  • anonymous
x=4
anonymous
  • anonymous
So you should have \(\frac{-11 \pm \sqrt{25}}{2(-2)}\)
anonymous
  • anonymous
I have to have a + and - answer
anonymous
  • anonymous
They could both be + or - depending on your other values.
anonymous
  • anonymous
But you will have 2 unless the part under the sqrt is 0
anonymous
  • anonymous
I have \[11+-\sqrt{25?}\div-4\]
anonymous
  • anonymous
It should be -11, not 11. Recall that the quadratic formula is \[ax^2 + bx +c=0 \implies x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
anonymous
  • anonymous
i got x=-9 and -14 over-4
anonymous
  • anonymous
okay that is right I have it in front of me
anonymous
  • anonymous
x = (-11 + 5 )/(-4) = -6/-4 = 3/2 x = (-11 - 5)/(-4) = -16/-4 = 4
anonymous
  • anonymous
if you let y be 0 than after you can write your equation as -2x^2+11x-12=0 or you can write this as 2x^2-11x+12=0 from this equation you can get the correct answer
anonymous
  • anonymous
You won't have any negative values for the x intercepts of this graph.
anonymous
  • anonymous
True I have been working on this too long I think thank you
anonymous
  • anonymous
Certainly =)

Looking for something else?

Not the answer you are looking for? Search for more explanations.