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anonymous
 5 years ago
let f(x) = lxl is f continuous at x = 0 why ????????
anonymous
 5 years ago
let f(x) = lxl is f continuous at x = 0 why ????????

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f is continuous because there are no gaps in the graph, in other words the point x=0 is defined > f(0) = 0 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is exact question i wrote ,,,, i also dont know ,,,,,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For a counter example imagine f(x) =x for x<0 and x>0 but f(x) = 1 for x=0 This means the y value jumps up 1 when you go from .00001 to 0 there is a gap

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know about limits?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The function is continuous if \(\lim_{x \rightarrow c^+} f(x) = \lim_{x \rightarrow c^} f(x) = f(c) \)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am new with limits ,,,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0As x gets closer and closer to c either from the infinity or +infinity sides, the function must approach the value f(c) in order to be continuous For f(x) = x we see that the limit from the left is approaching f(0)=0 along the y=x line. From the right we see it's approaching f(0) = 0 along the y=x line. Also the value of the function at x = 0 is 0 which is the value being approached from the left and the right. Therefore it is continuous about 0. (in fact it is continuous everywhere).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k ,,,, thnx a lot ,,,,,,,,,
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