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anonymous
 5 years ago
A toy train is pushed forward and released at Xi = 4.0 m with a speed of 2.5 m/s. It rolls at a steady speed for 2.0 s, then one wheel begins to stick. The train comes to a stop 7.7 m from the point at which it was released.
What is the train's acceleration after its wheel begins to stick?
anonymous
 5 years ago
A toy train is pushed forward and released at Xi = 4.0 m with a speed of 2.5 m/s. It rolls at a steady speed for 2.0 s, then one wheel begins to stick. The train comes to a stop 7.7 m from the point at which it was released. What is the train's acceleration after its wheel begins to stick?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is that Xi=4m for?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not sure thats how the problem is set up

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't think that 4m has anything to do with the problem. anyway. here. A___________________B_______C where A is the point that the train was released. B is where the wheel started to stick C is where it stopped From A to B, v=2.5m/s, it takes 2s to go A to B so t=2 AB= v*t = 2.5 * 2 = 5m The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m then BC= ACAB = 7.75 = 2.7m now consider BC v^2=u^2+2as where u is initial speed, in this case is 2.5m/s v is final speed, train stop at C so final speed=0, so v=0 a is acceleration s is displacement, which is BC=2.7m substitute all the number into equation, we have 0^2 = 2.5^2 + 2*a*2.7 0 = 6.25 + 5.4a a = 6.25/5.4 = 1.157 so acceleration is 1.157m/(s^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0very nice im gonna try to work it out. thanks! dont know how people remember this stuff though.. lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol only that equation you need to remember. there are a few equations that's very helpful. You'll surely remember them all. it's just the matter of time.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think youre good with physics can you help me with this one? (ill post it) search for my name thanks! =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not quite, but i'll try
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