A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/2^2. The acceleration period lasts for time 8.00 S, until the fuel is exhausted. After that, the rocket is in free fall.
Find the maximum height Vmax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s^2 .

- anonymous

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- anonymous

*58.8 m/s^2

- anonymous

i found the height when the fuel is exhausted which is = to 1880

- anonymous

the velocity at that point i think is 470 m/s

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## More answers

- anonymous

i think i have to find the distance it went after that and add it?

- anonymous

yep

- anonymous

that 1880, how did you come to that

- anonymous

1881.6 lol

- anonymous

yea rounded wrong LOL

- anonymous

470.4 m/s correct

- anonymous

I must complain about this question - it doesn't take into account the loss of mass as the fuel is ejected.

- anonymous

yea physics is a pain.. LOL

- anonymous

hey man it's simple physics lol. if you take mass into account, school students are doomed

- anonymous

i was using this formula Xf=Xi+(Vx)i Dt + 1/2Ax(Dt)^2

- anonymous

when ever i see a physics problems i get anxiety.. =(

- anonymous

ttt luv the pic

- anonymous

anyway, what's the distance traveled after fuel ran out?

- anonymous

i couldnt figure it out

- anonymous

im thinking i have to use this formula
V^2 = Vo^2+2a(y-yo)
Vo is the initial velocity which is 470 m/s?

- anonymous

ok, take upwards as possitive direction at the point where feul ran out, u=470.6m/s, a=-9.8m/s^2m, v=0m/s at max point.
use v^2=u^2+2aS

- anonymous

a=-9.8m/s^2 negative since acceleration downwards. gravity

- anonymous

uh huh!

- anonymous

so plug them in the equation, you'll find distance from no more gas point to max point, add this to distance from ground to ran out point to get max height

- anonymous

what do i plug in for S?

- anonymous

that's what you need to find. plug everything in to find S

- anonymous

0=470.6^2 + 2 (-9.8)S

- anonymous

yeap

- anonymous

11299

- anonymous

yea, looks reasonable
add this S to the S before(1881.6) you get max height

- anonymous

damn man youre a genius!

- anonymous

it took me an hour to figure out the first part =(

- anonymous

don t worry you will get used to it very soon, just keep practicing. All those problems more or less are the same

- anonymous

thanks! when can i buy you lunch!? LOL

- anonymous

lol what do you think, I eat physics for lunch hahaha. just kidding. I'm off to bed now. see ya.

- anonymous

haha thanks good night!

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