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anonymous
 5 years ago
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/2^2. The acceleration period lasts for time 8.00 S, until the fuel is exhausted. After that, the rocket is in free fall.
Find the maximum height Vmax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s^2 .
anonymous
 5 years ago
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/2^2. The acceleration period lasts for time 8.00 S, until the fuel is exhausted. After that, the rocket is in free fall. Find the maximum height Vmax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s^2 .

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i found the height when the fuel is exhausted which is = to 1880

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the velocity at that point i think is 470 m/s

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think i have to find the distance it went after that and add it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that 1880, how did you come to that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea rounded wrong LOL

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I must complain about this question  it doesn't take into account the loss of mass as the fuel is ejected.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea physics is a pain.. LOL

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey man it's simple physics lol. if you take mass into account, school students are doomed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i was using this formula Xf=Xi+(Vx)i Dt + 1/2Ax(Dt)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when ever i see a physics problems i get anxiety.. =(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0anyway, what's the distance traveled after fuel ran out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i couldnt figure it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im thinking i have to use this formula V^2 = Vo^2+2a(yyo) Vo is the initial velocity which is 470 m/s?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, take upwards as possitive direction at the point where feul ran out, u=470.6m/s, a=9.8m/s^2m, v=0m/s at max point. use v^2=u^2+2aS

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a=9.8m/s^2 negative since acceleration downwards. gravity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so plug them in the equation, you'll find distance from no more gas point to max point, add this to distance from ground to ran out point to get max height

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do i plug in for S?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's what you need to find. plug everything in to find S

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.00=470.6^2 + 2 (9.8)S

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea, looks reasonable add this S to the S before(1881.6) you get max height

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0damn man youre a genius!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it took me an hour to figure out the first part =(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0don t worry you will get used to it very soon, just keep practicing. All those problems more or less are the same

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks! when can i buy you lunch!? LOL

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol what do you think, I eat physics for lunch hahaha. just kidding. I'm off to bed now. see ya.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha thanks good night!
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