The company discovered that it costs $28 to produce 2 camera cases, $50 to produce 4 camera cases, and $140 to produce 10 camera cases. Using the quadratic function, find the cost of producing 12 cameras.

- anonymous

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

P = ax^2+bx+c, P is total production cost, x is number of cases. solve for a,b,c using the three values you are given,

- anonymous

so, 28 = 4a+2b+c
50 = 16a+4b+c
140 = 100a+10b+c

- anonymous

solve for a,b,c

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

how do i do that?

- anonymous

do you know how to do matrices?

- anonymous

no

- anonymous

okay
28 = 4a+2b+c ---------------------------------------->Eqaution 1
50 = 16a+4b+c ---------------------------------------> Eqn 2
140 = 100a+10b+c----------------------------------> eqn 3
do eqn 3 - eqn 1
and do eqn 2 - eqn 1
and post what you got here

- anonymous

still don't know how to figure it out

- anonymous

Can you subtract equation 1 from equation 2 and post it here?

- anonymous

38=12a+2b

- anonymous

how did you get 38?

- anonymous

32*

- anonymous

i mean 22*

- anonymous

ok so repost the correct equation again

- anonymous

22=12a+2b

- anonymous

okay good. Now, the same way, subtract equation 1 from equation 3

- anonymous

112=96a+8b

- anonymous

okay. Now, can you solve the set of equations
12a + 2b = 22
96a + 8b = 112
?

- anonymous

can you help me with it.

- anonymous

okay, have you learned how to solve two equations for two unknown variables in school?

- anonymous

not that i can remember.

- anonymous

you haven't done basic algebra in school yet?

- anonymous

alright anyway,
12a + 2b = 22 ------------>eqnA
96a + 8b = 112----------->eqnB

- anonymous

do you know substitution to solve for a and b?

- anonymous

okay just do 4 times eqn A and post it here.

- anonymous

what do you mean

- anonymous

If you multiply both sides of equation A by 4, what do you get?

- anonymous

48a+2b=88

- anonymous

try again

- anonymous

that's multiplying both sides by 4.

- anonymous

so 2b*4 = 2b?

- anonymous

usually when i've done that, i've never done it to all. be more specific.

- anonymous

48a+8b=88

- anonymous

if a =4, then 4a =16
so we multiply both sides by 4.
so if a+b = 4
then 4(a+b) =16

- anonymous

okay good,
so 48a + 8b = 88--------------->eqn. C
Do you notice what we did there? we multiplied equation B by 4 so that both equation A and equation C have the term 8B in them. So now subtract equation C from equation A.

- anonymous

i'm still completely confused

- anonymous

what are you confused about?

- anonymous

OK join me
http://www.dabbleboard.com/draw?b=Guest654407&i=0&c=ce1b368e8fb4c87408d1e26d13c93f5bf92f9032
will explain in detail there

- anonymous

okay i'm on there

Looking for something else?

Not the answer you are looking for? Search for more explanations.