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anonymous
 5 years ago
The company discovered that it costs $28 to produce 2 camera cases, $50 to produce 4 camera cases, and $140 to produce 10 camera cases. Using the quadratic function, find the cost of producing 12 cameras.
anonymous
 5 years ago
The company discovered that it costs $28 to produce 2 camera cases, $50 to produce 4 camera cases, and $140 to produce 10 camera cases. Using the quadratic function, find the cost of producing 12 cameras.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0P = ax^2+bx+c, P is total production cost, x is number of cases. solve for a,b,c using the three values you are given,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so, 28 = 4a+2b+c 50 = 16a+4b+c 140 = 100a+10b+c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know how to do matrices?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay 28 = 4a+2b+c >Eqaution 1 50 = 16a+4b+c > Eqn 2 140 = 100a+10b+c> eqn 3 do eqn 3  eqn 1 and do eqn 2  eqn 1 and post what you got here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0still don't know how to figure it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you subtract equation 1 from equation 2 and post it here?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so repost the correct equation again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay good. Now, the same way, subtract equation 1 from equation 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay. Now, can you solve the set of equations 12a + 2b = 22 96a + 8b = 112 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you help me with it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, have you learned how to solve two equations for two unknown variables in school?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not that i can remember.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you haven't done basic algebra in school yet?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright anyway, 12a + 2b = 22 >eqnA 96a + 8b = 112>eqnB

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know substitution to solve for a and b?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay just do 4 times eqn A and post it here.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you multiply both sides of equation A by 4, what do you get?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's multiplying both sides by 4.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0usually when i've done that, i've never done it to all. be more specific.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if a =4, then 4a =16 so we multiply both sides by 4. so if a+b = 4 then 4(a+b) =16

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay good, so 48a + 8b = 88>eqn. C Do you notice what we did there? we multiplied equation B by 4 so that both equation A and equation C have the term 8B in them. So now subtract equation C from equation A.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm still completely confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what are you confused about?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK join me http://www.dabbleboard.com/draw?b=Guest654407&i=0&c=ce1b368e8fb4c87408d1e26d13c93f5bf92f9032 will explain in detail there
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