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- anonymous

A company has 160 employees. The number of part-time workers is 7/9 the number of full-time workers. How many part-time and full-time workers does the company employ?

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- anonymous

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- anonymous

suppose x is the part-time workers and y is the full-time workers.
x = (7/9) y
the total employees is 160:
x+y=160
(7/9)y+y = 160
(16/9)y=160
y=160(9/16) -> y=90
then from x+y=160, we could get x=160-90=70

- anonymous

how did you get 16/9

- anonymous

7/9 y + y = 7/9 y + 9/9 y = 16/9 y

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- anonymous

thanks could i ask you a couple more questions

- anonymous

sure

- anonymous

A computer consultant charges $250 for each hour of consultation and $175 for each hour of programming for clients. In 8 hours of work, she earned $1625. How much time did she spend on each activity?

- anonymous

suppose x = hours of consulation
and y = hours of programming
the total hours of work is 8, so x+y = 8
She earned $1625 , so:
250x + 175y = 1625
now we have 2 equations, solve those and you'll get x and y

- anonymous

i got x = 3 and y=5

- anonymous

so it is trial and error

- anonymous

do you understand now?

- anonymous

yeap

- anonymous

draw the graph for the equation 2x-3y +9=0

- anonymous

2x-3y=-9
i usually find the x axis intersection and y-axis intersection first.
at x=0 -> y=3 , the point is (0, 3)
at y=0-> x=-9/2 , the point is (-9/2 , 0)
then just connect both point

- anonymous

it will be looked like this

- anonymous

thanks but how do you find (-9/2) on a graph

- anonymous

-9/2 = -4.5 , it's between 4 and 5

- anonymous

ok thanks

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