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anonymous
 5 years ago
For what values of x does the series P1n =1
(x−5)n
n2n converge absolutely?
converge conditionally? diverge? how do you even start this thing ?????
anonymous
 5 years ago
For what values of x does the series P1n =1 (x−5)n n2n converge absolutely? converge conditionally? diverge? how do you even start this thing ?????

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i cant read this, are those subscripts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you add mayh symbols

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0subscripts you can write a_n , or underscore

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0they are superscripts and i also need to add a sigma sign

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0superscripts is like exponent ^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohk i will just write so we have a fraction ((x5)^5)/(n2^n) and sigma n=1 to infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0∑n=1 to infinity for ((x5)^5)/(n2^n)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when x =0 clearly it converges

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when x is even you have

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when x > 5 it converges absolutely

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why would you say when x>5 it converges

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then its positive the numerator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think theres something wrong with the series i get for all x it converges

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm i wasthinking if x>5 then it will diverge because numerator will be positive and growing :

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and for 5 it is zero converges and then after that it negative growth

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no it will be constant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0remember the variable is n here inside the series

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if x = 10, you have (105)^5 or 5^5 in the numerator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you typed the question wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm ya i didn't pay attention to that :

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it should be (x5)^n / ( 2^n ) ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x5)^n / ( n2^n ) there is a n in front of 2 :

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok, so now its tougher

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait up i am going to put up a screen shot :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0they are asking for a radius of convergence

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm i thought we need to find limits :

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we can use the ratio test

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i think we can :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so we can use our scriblink

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.scriblink.com/index.jsp?act=phome&roomid=44&KEY=F71D8E165FCC9B3AA0E17782EDB164F0
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