For what values of x does the series P1n =1 (x−5)n n2n converge absolutely? converge conditionally? diverge? how do you even start this thing ?????

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For what values of x does the series P1n =1 (x−5)n n2n converge absolutely? converge conditionally? diverge? how do you even start this thing ?????

Mathematics
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i cant read this, are those subscripts
P ln ?
how do you add mayh symbols

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math *
subscripts you can write a_n , or underscore
they are superscripts and i also need to add a sigma sign
superscripts is like exponent ^
ohk i will just write so we have a fraction ((x-5)^5)/(n2^n) and sigma n=1 to infinity
∑n=1 to infinity for ((x-5)^5)/(n2^n)
when x =0 clearly it converges
i mean when x = 5
when x is even you have
when x > 5 it converges absolutely
why would you say when x>5 it converges
then its positive the numerator
i think theres something wrong with the series i get for all x it converges
hmm i wasthinking if x>5 then it will diverge because numerator will be positive and growing :|
and for 5 it is zero converges and then after that it negative growth
no it will be constant
remember the variable is n here inside the series
so if x = 10, you have (10-5)^5 or 5^5 in the numerator
oh wait a second
you typed the question wrong
hmm ya i didn't pay attention to that :|
it should be (x-5)^n / ( 2^n ) ?
the series
(x-5)^n / ( n2^n ) there is a n in front of 2 :|
oh ok, so now its tougher
wait up i am going to put up a screen shot :)
oh ok
1 Attachment
they are asking for a radius of convergence
hmm i thought we need to find limits :|
so we can use the ratio test
yes i think we can :)
ok so we can use our scriblink
which one
http://www.scriblink.com/index.jsp?act=phome&roomid=44&KEY=F71D8E165FCC9B3AA0E17782EDB164F0

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