anonymous
  • anonymous
For what values of x does the series P1n =1 (x−5)n n2n converge absolutely? converge conditionally? diverge? how do you even start this thing ?????
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
i cant read this, are those subscripts
anonymous
  • anonymous
P ln ?
anonymous
  • anonymous
how do you add mayh symbols

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anonymous
  • anonymous
math *
anonymous
  • anonymous
subscripts you can write a_n , or underscore
anonymous
  • anonymous
they are superscripts and i also need to add a sigma sign
anonymous
  • anonymous
superscripts is like exponent ^
anonymous
  • anonymous
ohk i will just write so we have a fraction ((x-5)^5)/(n2^n) and sigma n=1 to infinity
anonymous
  • anonymous
∑n=1 to infinity for ((x-5)^5)/(n2^n)
anonymous
  • anonymous
when x =0 clearly it converges
anonymous
  • anonymous
i mean when x = 5
anonymous
  • anonymous
when x is even you have
anonymous
  • anonymous
when x > 5 it converges absolutely
anonymous
  • anonymous
why would you say when x>5 it converges
anonymous
  • anonymous
then its positive the numerator
anonymous
  • anonymous
i think theres something wrong with the series i get for all x it converges
anonymous
  • anonymous
hmm i wasthinking if x>5 then it will diverge because numerator will be positive and growing :|
anonymous
  • anonymous
and for 5 it is zero converges and then after that it negative growth
anonymous
  • anonymous
no it will be constant
anonymous
  • anonymous
remember the variable is n here inside the series
anonymous
  • anonymous
so if x = 10, you have (10-5)^5 or 5^5 in the numerator
anonymous
  • anonymous
oh wait a second
anonymous
  • anonymous
you typed the question wrong
anonymous
  • anonymous
hmm ya i didn't pay attention to that :|
anonymous
  • anonymous
it should be (x-5)^n / ( 2^n ) ?
anonymous
  • anonymous
the series
anonymous
  • anonymous
(x-5)^n / ( n2^n ) there is a n in front of 2 :|
anonymous
  • anonymous
oh ok, so now its tougher
anonymous
  • anonymous
wait up i am going to put up a screen shot :)
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
they are asking for a radius of convergence
anonymous
  • anonymous
hmm i thought we need to find limits :|
anonymous
  • anonymous
so we can use the ratio test
anonymous
  • anonymous
yes i think we can :)
anonymous
  • anonymous
ok so we can use our scriblink
anonymous
  • anonymous
which one
anonymous
  • anonymous
http://www.scriblink.com/index.jsp?act=phome&roomid=44&KEY=F71D8E165FCC9B3AA0E17782EDB164F0

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