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anonymous

  • 5 years ago

For what values of x does the series P1n =1 (x−5)n n2n converge absolutely? converge conditionally? diverge? how do you even start this thing ?????

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  1. anonymous
    • 5 years ago
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    i cant read this, are those subscripts

  2. anonymous
    • 5 years ago
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    P ln ?

  3. anonymous
    • 5 years ago
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    how do you add mayh symbols

  4. anonymous
    • 5 years ago
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    math *

  5. anonymous
    • 5 years ago
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    subscripts you can write a_n , or underscore

  6. anonymous
    • 5 years ago
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    they are superscripts and i also need to add a sigma sign

  7. anonymous
    • 5 years ago
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    superscripts is like exponent ^

  8. anonymous
    • 5 years ago
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    ohk i will just write so we have a fraction ((x-5)^5)/(n2^n) and sigma n=1 to infinity

  9. anonymous
    • 5 years ago
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    ∑n=1 to infinity for ((x-5)^5)/(n2^n)

  10. anonymous
    • 5 years ago
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    when x =0 clearly it converges

  11. anonymous
    • 5 years ago
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    i mean when x = 5

  12. anonymous
    • 5 years ago
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    when x is even you have

  13. anonymous
    • 5 years ago
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    when x > 5 it converges absolutely

  14. anonymous
    • 5 years ago
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    why would you say when x>5 it converges

  15. anonymous
    • 5 years ago
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    then its positive the numerator

  16. anonymous
    • 5 years ago
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    i think theres something wrong with the series i get for all x it converges

  17. anonymous
    • 5 years ago
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    hmm i wasthinking if x>5 then it will diverge because numerator will be positive and growing :|

  18. anonymous
    • 5 years ago
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    and for 5 it is zero converges and then after that it negative growth

  19. anonymous
    • 5 years ago
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    no it will be constant

  20. anonymous
    • 5 years ago
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    remember the variable is n here inside the series

  21. anonymous
    • 5 years ago
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    so if x = 10, you have (10-5)^5 or 5^5 in the numerator

  22. anonymous
    • 5 years ago
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    oh wait a second

  23. anonymous
    • 5 years ago
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    you typed the question wrong

  24. anonymous
    • 5 years ago
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    hmm ya i didn't pay attention to that :|

  25. anonymous
    • 5 years ago
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    it should be (x-5)^n / ( 2^n ) ?

  26. anonymous
    • 5 years ago
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    the series

  27. anonymous
    • 5 years ago
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    (x-5)^n / ( n2^n ) there is a n in front of 2 :|

  28. anonymous
    • 5 years ago
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    oh ok, so now its tougher

  29. anonymous
    • 5 years ago
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    wait up i am going to put up a screen shot :)

  30. anonymous
    • 5 years ago
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    oh ok

  31. anonymous
    • 5 years ago
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    1 Attachment
  32. anonymous
    • 5 years ago
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    they are asking for a radius of convergence

  33. anonymous
    • 5 years ago
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    hmm i thought we need to find limits :|

  34. anonymous
    • 5 years ago
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    so we can use the ratio test

  35. anonymous
    • 5 years ago
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    yes i think we can :)

  36. anonymous
    • 5 years ago
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    ok so we can use our scriblink

  37. anonymous
    • 5 years ago
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    which one

  38. anonymous
    • 5 years ago
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    http://www.scriblink.com/index.jsp?act=phome&roomid=44&KEY=F71D8E165FCC9B3AA0E17782EDB164F0

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