how to sketch 1+ [2/(x+1)]

- anonymous

how to sketch 1+ [2/(x+1)]

- schrodinger

See more answers at brainly.com

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

u mean a graph?

- anonymous

r u der?

- anonymous

yes a graph

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

alright, lets take the given function as y
so, y=1+[2/(x+1)]

- anonymous

now, substitute x=0, u'll get y value, so this gives u one point on the graph like (x,y)
i think u know how to plot point on a graph , right?

- anonymous

yes

- anonymous

##### 1 Attachment

- anonymous

thank you very much lokisan ^.^

- anonymous

you still need to do what thinker was doing...i.e. drawing it yourself

- anonymous

and yeah...try plugging more point..x=-1,1, -2,2,....so on..to get a good graph :)

- anonymous

sry *points

- anonymous

and the graph that u get finally is a symmetric one, i.e. symmetric about the 1st & 3rd quadrants

- anonymous

This one shows both asymptotes.

##### 1 Attachment

- anonymous

thank you very much thinker!
=]

- anonymous

You should notice some qualitative aspects of the function to make your drawing easier. For example, as x approaches -1, the function approach plus or minus infinity, depending on which direction -1 is being approached.
As x goes to plus or minus infinity, the function goes to 1.

- anonymous

ur welcome @virtus :)

- anonymous

i'm a bit confused on the asymptotes bit i know we can determine one asymptote by looking at the denominator of the fraction but how did you get the other, y =1

- anonymous

Once you get a bit more advanced, you'll notice that your function is just a composition of functions and that what you've got is just a hyperbolic function (1/x) that has been translated by a horizontal shift (i.e. x goes to x+constant)) with the result of that multiplied by 2 (thereby pushing the corner of the hyperbola further out) and then the entire thing shifted up 1 unit.

- anonymous

\[y=1+\frac{2}{x+1}\]What happens as x gets larger without bound?

- anonymous

Very large positive x will make 2/(x+1) a very small positive number.
Very large negative x will make 2/(x+1) a very small negative number.
You'll be adding/subtracting very small amounts for large x. As x gets large, this effect is more pronounced.

- anonymous

So basically, the function approaches the value 1 and x approached plus or minus infinity.

- anonymous

You can see that in the plot.

- anonymous

Btw, the software I used to make that plot is free:
http://www.geogebra.org/cms/

- anonymous

got it @virtus?

- anonymous

oh well, we'll assume virtus has got it... :p

- anonymous

hahahhas sorry for late reply
THANK YOU SO SO MUCH!

- anonymous

np

- anonymous

ur wc

- anonymous

Use wolframalpha
http://www.wolframalpha.com
just write your formula and hit Enter

Looking for something else?

Not the answer you are looking for? Search for more explanations.