## anonymous 5 years ago how to sketch 1+ [2/(x+1)]

1. anonymous

u mean a graph?

2. anonymous

r u der?

3. anonymous

yes a graph

4. anonymous

alright, lets take the given function as y so, y=1+[2/(x+1)]

5. anonymous

now, substitute x=0, u'll get y value, so this gives u one point on the graph like (x,y) i think u know how to plot point on a graph , right?

6. anonymous

yes

7. anonymous

8. anonymous

thank you very much lokisan ^.^

9. anonymous

you still need to do what thinker was doing...i.e. drawing it yourself

10. anonymous

and yeah...try plugging more point..x=-1,1, -2,2,....so on..to get a good graph :)

11. anonymous

sry *points

12. anonymous

and the graph that u get finally is a symmetric one, i.e. symmetric about the 1st & 3rd quadrants

13. anonymous

This one shows both asymptotes.

14. anonymous

thank you very much thinker! =]

15. anonymous

You should notice some qualitative aspects of the function to make your drawing easier. For example, as x approaches -1, the function approach plus or minus infinity, depending on which direction -1 is being approached. As x goes to plus or minus infinity, the function goes to 1.

16. anonymous

ur welcome @virtus :)

17. anonymous

i'm a bit confused on the asymptotes bit i know we can determine one asymptote by looking at the denominator of the fraction but how did you get the other, y =1

18. anonymous

Once you get a bit more advanced, you'll notice that your function is just a composition of functions and that what you've got is just a hyperbolic function (1/x) that has been translated by a horizontal shift (i.e. x goes to x+constant)) with the result of that multiplied by 2 (thereby pushing the corner of the hyperbola further out) and then the entire thing shifted up 1 unit.

19. anonymous

$y=1+\frac{2}{x+1}$What happens as x gets larger without bound?

20. anonymous

Very large positive x will make 2/(x+1) a very small positive number. Very large negative x will make 2/(x+1) a very small negative number. You'll be adding/subtracting very small amounts for large x. As x gets large, this effect is more pronounced.

21. anonymous

So basically, the function approaches the value 1 and x approached plus or minus infinity.

22. anonymous

You can see that in the plot.

23. anonymous

Btw, the software I used to make that plot is free: http://www.geogebra.org/cms/

24. anonymous

got it @virtus?

25. anonymous

oh well, we'll assume virtus has got it... :p

26. anonymous

hahahhas sorry for late reply THANK YOU SO SO MUCH!

27. anonymous

np

28. anonymous

ur wc

29. anonymous

Use wolframalpha http://www.wolframalpha.com just write your formula and hit Enter