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anonymous

  • 5 years ago

attention amistre64!!

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  1. anonymous
    • 5 years ago
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    I have a question of vectors and i need help with that. so can you plz spare some time on it? i am attaching the question below

  2. anonymous
    • 5 years ago
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    1 Attachment
  3. amistre64
    • 5 years ago
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    vectors eh.... i was trying to catch up on them last night, little arrows with direction and magnitude...<x,y>

  4. amistre64
    • 5 years ago
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    so what is a vector normal to the surface like? anything like a position vector in R^2?

  5. anonymous
    • 5 years ago
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    oh nevermind. "lokisan" has already answered it =) i'll post the link and u can see it

  6. anonymous
    • 5 years ago
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    http://openstudy.com/groups/mathematics#/updates/4da986dfd6938b0b56a2a54d

  7. amistre64
    • 5 years ago
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    thanks :) Im still wet behind the ears when it comes to adding the zplane ;)

  8. amistre64
    • 5 years ago
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    normal to the surface means perpendicular to the surface

  9. anonymous
    • 5 years ago
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    yes.

  10. amistre64
    • 5 years ago
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    the ijk in there are vector identifiers right?

  11. anonymous
    • 5 years ago
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    yes.

  12. amistre64
    • 5 years ago
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    correspond with xyz if I recall correctly

  13. amistre64
    • 5 years ago
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    but then i do not recall correctly lol... we foil out the left part right?

  14. amistre64
    • 5 years ago
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    does 3x^2 (xi) = 3x^3 i?

  15. anonymous
    • 5 years ago
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    i would suggest you revise it =)

  16. amistre64
    • 5 years ago
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    lol.... give me a week, and ill be a pro at it :) but for know, its over me head

  17. anonymous
    • 5 years ago
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    sorry can't wait that long =)

  18. amistre64
    • 5 years ago
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    you tell me the steps you took and ill see if I cant mess them up ... sound good?

  19. amistre64
    • 5 years ago
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    cross product sounds familiar.....

  20. amistre64
    • 5 years ago
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    ab = absin(t)n is looking good to me

  21. anonymous
    • 5 years ago
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    To find Normal vector find r'(v)/||r'(v)||

  22. anonymous
    • 5 years ago
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    In this specific case you find the del

  23. amistre64
    • 5 years ago
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    ||r'V|| is the length or magnitude.... of the vector , i think

  24. anonymous
    • 5 years ago
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    You find the dell and it leads to a messy vector. Normal is <x/(16x^2+16y^2+1), 3/(16x^2...), sq rt (16x^2...)/sq rt (x^2+y^2). I have no reason why they would ask a question that would get such a result unless it is a challenge or competition question.

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