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anonymous
 5 years ago
attention amistre64!!
anonymous
 5 years ago
attention amistre64!!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have a question of vectors and i need help with that. so can you plz spare some time on it? i am attaching the question below

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0vectors eh.... i was trying to catch up on them last night, little arrows with direction and magnitude...<x,y>

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so what is a vector normal to the surface like? anything like a position vector in R^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh nevermind. "lokisan" has already answered it =) i'll post the link and u can see it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/groups/mathematics#/updates/4da986dfd6938b0b56a2a54d

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thanks :) Im still wet behind the ears when it comes to adding the zplane ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0normal to the surface means perpendicular to the surface

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the ijk in there are vector identifiers right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0correspond with xyz if I recall correctly

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0but then i do not recall correctly lol... we foil out the left part right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0does 3x^2 (xi) = 3x^3 i?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i would suggest you revise it =)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol.... give me a week, and ill be a pro at it :) but for know, its over me head

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry can't wait that long =)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you tell me the steps you took and ill see if I cant mess them up ... sound good?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0cross product sounds familiar.....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ab = absin(t)n is looking good to me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To find Normal vector find r'(v)/r'(v)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In this specific case you find the del

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0r'V is the length or magnitude.... of the vector , i think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You find the dell and it leads to a messy vector. Normal is <x/(16x^2+16y^2+1), 3/(16x^2...), sq rt (16x^2...)/sq rt (x^2+y^2). I have no reason why they would ask a question that would get such a result unless it is a challenge or competition question.
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