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in this case....x =-5

so you just make x+5=0

then solve for x?

Try finding the lim as x goes to 0

that is correct, you want to know what vale of x can never be used

line not lint, but if it is in macaroni art, use zitis

so to find the equation of the vertical asymptote of the function f(x)=4/x+5
what is the answer?

i am so confused?

no

what value of x makes the bottom of your fraction there go bad?

anything negative?

-5

correct! so that is your VA

x = -5 is the VA

ok i get it now,

there i graphed in it matlab shows you what is happening in case the visual aspect helps

you got that in crayon? :)

then how do i get horizontal asym to 5x^2-4/(x+1)

look at the graph that should help you visualize it.

the right side there seems off, but that might be the zoom limit

ill try to fix it

if we simply do a shortcut and divide all the numbers by x, we get the top to be 5x

there you go now its a bit better

thats better, but the your asymptotes gone parabolic instead of linear :)

5x^2-4/(x+1)
the top and bottom differ by 1 degree, so the asymptote is linear

sorry i had the equation not copy and pasted wrong lol here is the correct result

yay!! i knew you could do it :)

man im just trying to help him out?

youre doing great....

im pretty sure when you learn these things it helps to look at a graph

it does, i am visual alot, the analysis part still gets my brain tied in knots

sorry i thought you were being sarcastic there