anonymous 5 years ago A triangle has vertices at A(-2, -2), B(0, -9) & C(1, 2). Find BC.

1. anonymous

can u help with probability

2. anonymous

ok look graph all the points and use the formula $D(p1,p2)= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$ in this case $D(B,C)= \sqrt{(0-1)^{2}+(-9-2)^{2}}$ good luck

3. anonymous