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intersection point is x=1

alright so that will become your upper bound of integration.

So 1 is your outer boundary, the origin the other: (0,1)

yup

alright so on your sketch which function lies higher in the y direction?

g(x)

soo..\[\int\limits_{0}^{1}g(x)dx-\int\limits_{0}^{1}f(x)dx\]

thank you so much! :)

np

alright, i'll keep that in mind, thank you! :)