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anonymous

  • 5 years ago

In order to find the area enclosed between the functions f(x)=x^3 and g(x)=2x-x^3, at x=-2 to x=1, what is the minimum number of integrals that can be used?

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  1. amistre64
    • 5 years ago
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    minimum number of integrals?

  2. anonymous
    • 5 years ago
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    yes, i'm not sure what it means >.< it's on my exam review. the answer is 3

  3. amistre64
    • 5 years ago
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    you use one integral to find the area of the top function, one to find the area of the bottom funtion, then subtract the botton from the top... how many....thats an odd question..

  4. anonymous
    • 5 years ago
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    then why is the answer 3? 2 integrals to find the area and then algebra to subtract one from the other? what im confused now

  5. anonymous
    • 5 years ago
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    *find the areas

  6. amistre64
    • 5 years ago
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    LOL ..... now youre like me ;)

  7. anonymous
    • 5 years ago
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    haha i have no idea

  8. amistre64
    • 5 years ago
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    i have found that test do include human error.

  9. anonymous
    • 5 years ago
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    haha i have no idea

  10. anonymous
    • 5 years ago
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    it's 3 because f(x) uses one integral, and both elements in g(x) can have their seperate integral.

  11. anonymous
    • 5 years ago
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    also if you think about using right endpoints, and left endpoints to calculate the area (or even midpoints), you will have 3 areas to calculate under the curve if seperated by 1 unit increments

  12. anonymous
    • 5 years ago
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    the reason why the minimum is 3 is because only using 2 integrals would leave you with an area that is not accurate wat so ever, whereas if you use 3,m because there are 4 x values between -2 and 1, your area found will be accurate when u average out left endpoints, and right endpoints.

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