anonymous
  • anonymous
In order to find the area enclosed between the functions f(x)=x^3 and g(x)=2x-x^3, at x=-2 to x=1, what is the minimum number of integrals that can be used?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
minimum number of integrals?
anonymous
  • anonymous
yes, i'm not sure what it means >.< it's on my exam review. the answer is 3
amistre64
  • amistre64
you use one integral to find the area of the top function, one to find the area of the bottom funtion, then subtract the botton from the top... how many....thats an odd question..

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anonymous
  • anonymous
then why is the answer 3? 2 integrals to find the area and then algebra to subtract one from the other? what im confused now
anonymous
  • anonymous
*find the areas
amistre64
  • amistre64
LOL ..... now youre like me ;)
anonymous
  • anonymous
haha i have no idea
amistre64
  • amistre64
i have found that test do include human error.
anonymous
  • anonymous
haha i have no idea
anonymous
  • anonymous
it's 3 because f(x) uses one integral, and both elements in g(x) can have their seperate integral.
anonymous
  • anonymous
also if you think about using right endpoints, and left endpoints to calculate the area (or even midpoints), you will have 3 areas to calculate under the curve if seperated by 1 unit increments
anonymous
  • anonymous
the reason why the minimum is 3 is because only using 2 integrals would leave you with an area that is not accurate wat so ever, whereas if you use 3,m because there are 4 x values between -2 and 1, your area found will be accurate when u average out left endpoints, and right endpoints.

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