Im graphing a parabola using the function; y = 3x^2 - 6x + 1. My question says what is the equation of the axis of symmetry, how would I solve it? (simple easy version plzz) xD

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Im graphing a parabola using the function; y = 3x^2 - 6x + 1. My question says what is the equation of the axis of symmetry, how would I solve it? (simple easy version plzz) xD

Mathematics
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make a sketch of the function from -3 to +3 in intervals of 1. Then think about the questions again it should become more clear
-b/2a
-middle#/2(first#) include signs

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x = --6/2(3) = 6/6 = 1
oh sorry i did not reply hold on let me read and try to comprehend what you wrote.
now looking at this you could also solve it graphically if that helps understand why amistre's equation is what it is
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how would you solve it grapically then, i am having a hard time putting the info together.... ;P
ok so when they say axis of symmetry the mean, graphically, where on the graph could you make a line so that if you put a mirror on that line you would see a mirror image of whatever is on the other side. so here it was y=1, which is a straight line going up and down from x=1. so if you put a mirror on that line, looking at the graph, would you see the mirror image?
I entered the equation into the graphing calculator and ok yea its y = 1 right.... Yes you would wouldnt you?...
see a mirror image. that is
i dunno that is something you cant explain, you just have to look at the graph and see what i mean since it is really obvious in this case. just think about it and you will get it :)
haha blonde here!! But ya... maybe in a few days i'll figure it out jk lol (:
ok ya just looked at it and im pretty sure i figured it out... thx!! (: haha not a math kinda girl im a writer.. :P but anyways thx!!

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